Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
ANSWER

EXPLANATION
We write the function such that both the numerator and the denominator are prime.
An example of a rational function with no vertical asymptotes and no holes is

For the above rational function, the denominator is never zero, so there are no vertical asymptotes.
Also the highest common factor for the numerator and the denominator is 1 so there are no holes.
Answer is option C 19.64 sq units
We can see that
both lines intersects at origin
so, the solution is x=0 and y=0
now, we will check each options
option-A:


now, we can set them equal
and then we can solve for x



now, we can find y


so, solution is x=0 and y=0
so, this correct...........Answer
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