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3 years ago

Yesterday,Jack drove 39 and one half.He used 1 and one fourth gallons of gasoline. What is the unit rate for miles per gallon?

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

5 0

39.5/1/25=31.6
...........

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Step-by-step explanation:

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where the $z$ -component is obtained from

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with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

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Step-by-step explanation:

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​Yesterday,Jack drove 39 and one half.He used 1 and one fourth gallons of gasoline. What is the unit rate for miles per​ gallon?

Yesterday,Jack drove 39 and one half.He used 1 and one fourth gallons of gasoline. What is the unit rate for miles per gallon?