<span>d=
d=
d=
d= 10.00 </span><span>x1 y1 x2 y2
d=
7 3 13 11
</span>
3(5y-6)-2y=8
15y-18-2y=8
13y-18=8
13y=26
y=2
That is because you have the expression you can substitute it on the system.( hope this helps)
Answer:
a) y = 0.74x + 18.99; b) 80; c) r = 0.92, r² = 0.85; r² tells us that 85% of the variance in the dependent variable, the final average, is predictable from the independent variable, the first test score.
Step-by-step explanation:
For part a,
We first plot the data using a graphing calculator. We then run a linear regression on the data.
In the form y = ax + b, we get an a value that rounds to 0.74 and a b value that rounds to 18.99. This gives us the equation
y = 0.74x + 18.99.
For part b,
To find the final average of a student who made an 83 on the first test, we substitute 83 in place of x in our regression equation:
y = 0.74(83) + 18.99
y = 61.42 + 18.99 = 80.41
Rounded to the nearest percent, this is 80.
For part c,
The value of r is 0.92. This tells us that the line is a 92% fit for the data.
The value of r² is 0.85. This is the coefficient of determination; it tells us how much of the dependent variable can be predicted from the independent variable.
Answer:
True.
Step-by-step explanation:
When we look at a cylinder, it has be observed that it has 3 parts or 3 shapes to it.
These 3 parts or shapes are referred to as the net of a cylinder.
This 3 parts include
a. A circle at the top
b. A circle at the bottom.
c. A rectangle.
The circle at the bottom gives us the base of the cylinder while the rectangle is curved when forming the cylinder and it is due to this that we have the curved surface area of the cylinder.
It is important to know that there is a relationship between the length of one of the edges of the rectangle and the circumference of the base of the cylinder such that, the length of one of the edges of the rectangle is equal to or equivalent to the circumference of each circular base.
