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2 years ago

5

Sally can type 100 words per minute while David can type 200 words per minute. Given these numbers, society would be better off

if which one of the two was employed as a typist

1 answer:

frozen [14]2 years ago

5 0

Answer:

David

Step-by-step explanation:

He types faster

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A shop sells fruit in two types of gift boxes: standard and deluxe. Each standard box contained 1kg of peaches and 2kg of apples

Morgarella [4.7K]

Let's call the number of standard boxes sold x and the number of deluxe boxes sold y.
The kg of peaches sold will be 1 for each standard box and 2 for each deluxe, so we know:
x + 2y = 12
The kg of apples sold will be 2 for each standard box and 1.5 for each deluxe, so:
2x + 1.5y = 14. Now we solve the two equations as a system:
From the 1st one:
x = 12 - 2y
We substitute in the second one:
2(12 - 2y) +1.5y = 14;
24 - 4y +1.5y = 14;
-2.5y = -10;
y = 10/2.5 = 4;
Now we substitute in the first equation:
x = 12 - 2y = 12 - 2*4 = 12 - 8 = 4.
So the shop sold 4 standard boxes (x) and 4 deluxe boxes (y).

5 0

2 years ago

The number of days, d, of snow is not 7

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2 years ago

Is x=4 and y=5 perpendicular

faltersainse [42]

True!

<h2>Explanation:</h2>

The Cartesian coordinate system is formed by two perpendicular axes, which are the x-axis and y-axis. In this problem, we are given two lines:

$x=4 \ and \ y=5$

The line $x=4$ is parallel to the y-axis and has an undefined slope.
The line $y=5$ is parallel to the x-axis and has a slope of zero.

Since the x and y-axes are perpendicular, then the lines $x=4 \ and \ y=5$ are also perpendicular.

<h2>Learn more:</h2>

Cartesian coordinate system: brainly.com/question/2141683

#LearnWithBrainly

6 0

2 years ago

The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad

Leya [2.2K]

<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. $Q_1$ = 14

Median or second quartile i.e. $Q_2$ = 18

Third quartile or upper quartile i.e. $Q_3$ =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. $Q_1$ = 26

Median or second quartile i.e. $Q_2$ = 30

Third quartile or upper quartile i.e. $Q_3$ = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. $Q_3-Q_1$

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

$8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5$

Hence, the number is : 1.5

6 0

3 years ago

2 1/2 x 1 1/2 pls help

Yuri [45]

The answer is 3.75 or 15/4 or 3 3/4

5 0

3 years ago

Read 2 more answers