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kodGreya [7K]
3 years ago
8

There are 27 students in a class. 13 are

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

Answer: Seniors: 13/27 Juniors:14/27

Step-by-step explanation:

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Graph the inequality. 3x+4y>20
gogolik [260]

Answer:

y=-3/4x+5

Step-by-step explanation:

3x+4y>20

4y>-3x+20

y>-3/4x+5

3 0
3 years ago
Write a mixed number
djyliett [7]

Answer:

2¾ , 3¾

Step-by-step explanation:

Anything with a combination of fraction and whole number is a mixed number. so possibilities are pretty much endless

5 0
3 years ago
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Perimeter and Circumference! Only 5 questions
Wittaler [7]

Answer:

1) 17.5

2)43.96

3)20

4) 15.7

5)25

Step-by-step explanation:

ohhhh yes

4 0
3 years ago
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The vertex of the graph of y = -4(x + 3)² + 2 is<br> DONE
wariber [46]

A parabola is a mirror-symmetrical planar curve that is nearly U-shaped. The vertex of the parabola will lie at (-3,2).

<h3>What is the Equation of a parabola?</h3>

A parabola is a mirror-symmetrical planar curve that is nearly U-shaped.

y = a(x-h)² + k

where,

(h, k) are the coordinates of the vertex of the parabola in the form (x, y);

a defines how narrower is the parabola, and the "-" or "+" that the parabola will open up or down.

Comparing the given equation with the equation of a parabola, we will get,

y =  a(x -h)² + k

y = -4(x+3)² + 2

Hence, the vertex of the parabola will lie at (-3,2).

Learn more about Parabola:

brainly.com/question/8495268

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5 0
3 years ago
In a two-digit number, the tens digit is 5 less than the units digit. The number itself is five more than three times the sum of
Luden [163]

Given:

In a two-digit number, the tens digit is 5 less than the units digit.

The number itself is five more than three times the sum of its digits.

To find:

The number.

Solution:

Let the two digit number is ab. So,

ab=10a+b

Tens digit is 5 less than the units digit.

a=b-5       ...(i)

The number itself is five more than three times the sum of its digits.

10a+b=3(a+b)+5

10a+b=3a+3b+5

10a+b-3a-3b=5

7a-2b=5          ...(ii)

Using (i) and (ii), we get

7(b-5)-2b=5

7b-35-2b=5

5b=5+35

5b=40

b=8

Putting b=8 in (i), we get

a=8-5

a=3

Therefore, the required number is 38.

5 0
3 years ago
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