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ryzh [129]
3 years ago
12

during photosynthesis water and carbon dioxide react to from oxygen and glucose how do the products differ from the reactants

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

Those are the waste products

Explanation:

Glucose and oxygen are produced as a waste product as a result of photosynthesis

You might be interested in
I have a question on my Chem homework. It's asking "How many molecules of N2O4 are in 76.3 g N2O4? The molar mass of N2O4 is 92.
evablogger [386]
Here, Molar mass of N2O4 = 92.02 g/mol
So, Number of molecules in 1 mole (92.02 g) = 6.023 * 10²³
Number of molecules in 76.3 g = 6.023 * 10²³ / 92.02  * 76.3
= 6.023 * 10²³ / 1.20
= 5 * 10²³ 

In short, Your Answer would be approx. 5 * 10²³ molecules

Hope this helps!
7 0
3 years ago
7-¿Cuántos moles de CO2 estarán encerrados en un recipiente metálico a una presión de 1.10 Atm. y una temperatura de 31 °C, sabi
Aleks [24]

Answer:

7- 0.69 moles.

8- El nuevo volumen es 3.8L.

Explanation:

7- Usando la ley general de los gases:

PV = nRT

PV / RT = n

<em>P es presión = 1.10atm</em>

<em>V es volumen = 15.70L</em>

<em>R es constante de los gases = 0.082atmL/molK</em>

<em>T es temperatura absoluta = 31°C + 273.15K = 304.15K</em>

<em />

Reemplazando:

1.10atm*15.70L / 0.082atmL/molK*304.15K = n

<h3>0.69 moles</h3><h3 />

8- La ley combinada de los gases establece como ecuación:

P1V1 / T1 = P2V2 / T2

<em>Donde P1 es la presión inicial = 760mmHg</em>

<em>V1 volumen inicial = 2L</em>

<em>T1 es temperatura absoluta = 273.15 + 27 = 300.15K</em>

<em>P2 = 380mmHg</em>

<em>T2 = 12°C + 273.15 = 285.15K</em>

<em />

Reemplazando:

760mmHg*2L / 300.15K = 380mmHg*V2 / 285.15K

3.8L = V2

<h3>El nuevo volumen es 3.8L</h3>
4 0
2 years ago
ХИМИЯ СОЧ
andre [41]

Answer:

thank you for free point

5 0
3 years ago
Read 2 more answers
Horizontal lines indicating a phase change will be at different temperatures depending on the substance.
fredd [130]

Answer:

true

Explanation:

I just know

ieuehdjrj

4 0
3 years ago
Read 2 more answers
A gas has a volume of 6.6 L at a temperature of 40 C. What is the volume of
zaharov [31]

Answer:

6.07 L

Explanation:

It appears that the reading has been made at constant pressure .

At constant pressure , the gas law formula is

V/T = constant  V is volume and T is temperature of the gas.

V₁ / T₁ = V₂ / T₂

V₁ = 6.6 L ,

T₁ = 40°C

= 273 + 40

= 313 K

T₂ = 15+ 273

= 288K

V₂ = ?

Putting the values in the formula above

6.6 / 313  = V₂ / 288

V₂ = 6.07 L.

8 0
3 years ago
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