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2 years ago

A bell hanging at the top of a tower has 8,550 j of energy. If it has a mass of 20 kg find the height of the Bell

Chemistry

1 answer:

kogti [31]2 years ago

3 0

43.62m

Explanation:

Given parameters:

Energy = 8550J

Mass of bell = 20kg

Unknown:

Height of the bell = ?

Solution:

As this state, the bell possesses potential energy. Potential energy is the energy at rest in a body. It is due to the position of the body.

Potential energy = m g h

m is the mass of the body

g is the acceleration due to gravity of the body

h is the height of the body

The unknown is h and we should solve for it.

g = 9.8m/s²

Input the variables;

8550 = 20 x 9.8 x h

h = 43.62m

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

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density of a piece of ebony wood is 1.174 g/ml. what is the volume in quarts of a 2.1549 lb piece of this ebony wood?

lapo4ka [179]

0.88qt

Explanation:

Given parameters:

Density of ebony wood = 1.174g/ml

Mass of wood = 2.1549lb

Unknown:

Volume of the wood in quarts = ?

Solution:

Density is defined as the mass per unit volume of a substance.

Mass is the quantity of matter the wood contains.

Volume is the space it occupies.

To solve this problem, convert the mass form pounds into grams and plug into the density equation to find volume.

Then convert the volume from mL to quarts.

Density = $\frac{mass}{volume}$

Volume = $\frac{mass}{density}$

1 pound = 453.592g

2.1549 lb = 2.1549 x 453.592 = 977.5g

Volume = $\frac{977.5}{1.174}$ = 832.6mL

1 quart = 946.353mL

Therefore 832.6mL x $\frac{1qt}{946.353}$ = 0.88qt

learn more:

Density brainly.com/question/8441651

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7 0

3 years ago

How many g of MgCO3(s) are needed to make 1.2 L of 1.5 M MgCl2(aq) solution?

maw [93]

Molar mass of MgCO3 is 84.313 g/mol
You can calculate this from data on the periodic table:
Molar mass Mg = 24.305g/mol
molar mass C = 12.011g/mol
molar mass O = 15.999g/mol mass 3 mol = 47.997g
Total = 84.313g/mol

Mass to be used in 1.2L of 1.5M solution = 84.313g * 1.2L * 1.5mol /L = 151.763g
I have not taken significant figures into account
The balanced equation you provide is not necessary in this calculation

4 0

2 years ago

Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802

Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo ( $Q$ ), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto ( $\bar {Q}$ ), en kilojoules por mol, dividido por su masa molar ( $M$ ), en gramos por mol: