Let's assume
length of Ribbon A is A
length of Ribbon B is B
length of Ribbon C is C
we are given
A=B+20% of B
A=1.2B
B=C-20% of C
B=0.80C
now, we can find relation between A and C
A=1.2B
we can plug B
A=1.2*0.80C
A=0.96C
so,
Ribbon A is 4 % shorter than Ribbon C.......Answer
2. Equals 307.629 because if you line up the decimals when you and then you should get your right answer
44 students because half of 44 is 22 and half of the class passed
The average is 105.5. To find the average, you have to add up all numbers, 63+148=211. Now you have to divide by how many numbers there are, 211÷2=105.5
Pretty Sure Its B I had this question Too
