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ipn [44]
2 years ago
12

A 900-kg car traveling east at 15. 0 m/s suddenly collides with a 750-kg car traveling north at 20. 0 m/s. The cars stick togeth

er after the collision. In what direction does the wreckage move just after the collision?.
SAT
1 answer:
dexar [7]2 years ago
4 0

By conservation of momentum,

(900 kg) (15.0 m/s) i + (750 kg) (20.0 m/s) j = (900 kg + 750 kg) v

where v is the velocity vector of the combined cars. Solve for v :

(13,500 i + 15,000 j) kg•m/s = (1650 kg) v

v ≈ (8.18 i + 9.09 j) m/s

Then the direction of v relative to East is θ such that

tan(θ) ≈ 9.09/8.18   ⇒   θ ≈ 48.0°

so the wreckages would move at approximately 48.0° north of east.

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company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul
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Sampling distribution involves the proportions of a data element in a given sample.

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\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]

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