<h3>Rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr</h3><h3><u>Solution:</u></h3>
Given that,
A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream
Therefore,
Upstream distance = 165 km
Upstream time = 3 hours
<h3><u>Find upstream speed:</u></h3>

Thus upstream speed is 55 km per hour
Downstream distance = 510 km
Downstream time = 6 hours
<h3><u>Find downstream speed:</u></h3>

Thus downstream speed is 85 km per hour
<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then</u></em>
Speed downstream = u + v km/hr
Speed upstream = u - v km/hr
Therefore,
u + v = 85 ----- eqn 1
u - v = 55 ----- eqn 2
Solve both
Add them
u + v + u - v = 85 + 55
2u = 140
u = 70
<em><u>Substitute u = 70 in eqn 1</u></em>
70 + v = 85
v = 85 - 70
v = 15
Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr
Answer:
- 2/3
Step-by-step explanation:
TRUST ME ON THIS; PERSON ABOVE ME IS WRONG!! pls give me brainliest!!
Answer:
ummm i don't see anything
Answer:
38=7x-y
Step-by-step explanation:
standard form= Ax+By+C
(y-3=7(x-5))
(y-3=7x-35)+3 to both sides
(y=7x-38) +38 to both sides
(y+38=7x) -y to both sides
38=7x-y
you have to move the 38 and y because if you moved the x value, than A becomes negative and it can't be in standard form
Answer:
1/600, 6/100, 1/1400
Step-by-step explanation: