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2 years ago

What is the solution to the trigonometric inequality 2sin(x)+3>sin^2(x) over the interval 0<=x<=2pi radians?

Mathematics

1 answer:

densk [106]2 years ago

5 0

Answer:

A 2-column table with 6 rows. Column 1 is labeled x with entries 1.99, 1.999, 1.9999, 2.0001, 2.001, 2.01. Column 2 is labeled f (x) with entries 0.505, negative 0.827, 0.306, negative 0.306, 0.827, negative 0.506.

Find Limit of f (x) as x approaches 2 f(x), if it exists.

0.3

DNE

Step-by-step explanation:

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A baker decorates 42 cupcakes in 30 minutes. She decorates cupcakes at a constant rate. How many cupcakes can the baker decorate

jolli1 [7]

Divide 42 by 30 and that should be your correct answer.

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3 years ago

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PLS HELP, I need help due today Math questions, I will mark brainiest if correct

Kryger [21]

The first answer is -1.4

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3 years ago

Plz reanswer it If (x+4): (3x+1) is the duplicate ratio of 3:4 find the value of x.

Rzqust [24]

Answer: x = 13/5

Explanation:

(x+4)/(3x+1) = 3/4

Cross multiply:

4(x+4) = 3(3x+1)
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3 years ago

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If you roll a fair six-sided die and a fair four-sided die, what is the probability that neither die shows a 1?

Masja [62]

For the first die, 5 out of 6 are not 1.
That is 5/6.
For the second die, 3 out of 4 are not 1.
That is 3/4.
Multiply 5/6 by 3/4 to get the probability.
5/6 x 3/4 = 20/72
Simplify once to get 10/36.
Do it again to get 5/18.
In decimal form it is 0.2777 and in percent form it is 27.77%.
Hope this helps!

3 0

3 years ago

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

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3 years ago