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schepotkina [342]
2 years ago
9

What is the easiest way of simplifying √27

Mathematics
2 answers:
RUDIKE [14]2 years ago
8 0

\sqrt{27 } \\  \\  =  3 \sqrt{3}

hoa [83]2 years ago
3 0

Answer: 3\sqrt{3}

Step-by-step explanation:

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Solve the inequality and graph its solution...<br> 3+v≤-9
xxTIMURxx [149]

Answer:

v≤-12, and the graph is left 12  

Step-by-step explanation:

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2 years ago
I need helpppp with 1-9
BigorU [14]
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lisov135 [29]

Answer:

x = 58

y = 90

Step-by-step explanation:

  • This is a rhombus becuase it a quadralterial and it has four right triangles, and it diagonals bisect each others so it cant be a trapezoid, and paralleolgram. and it doesnt have four right corner angles so it cant be a square or rectangle or kite.

A rhombus inner angle measure is 90 degrees.

So

y = 90

This means the upper left angle of the top triangle measure is 58 becuase triangle interior theorem.

Since a rhombus bisects angles, angle x measure 58.

7 0
3 years ago
Read 2 more answers
Help this is due tomorrow!!!
r-ruslan [8.4K]

Answer:

V=4/3*3.14*r^3

V=4/3*3.14*3^3

V=113.1

Volume of Himiphere= Volume of sphere/2

113.1/2

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Step-by-step explanation:

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4 0
2 years ago
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Find the area of each sector shown (the shaded section)
mihalych1998 [28]

Answer:

The area of the sector (shaded section) is 29.51 m^{2}.

Step-by-step explanation:

Area of a sector = (θ ÷ 360) \pir^{2}

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = \frac{diameter}{2}

 = \frac{26}{2} = 13 m

θ = 360 - (180 + 160)

  = 360 - 340

  = 20^{o}

Thus,

area of the given sector = \frac{20}{360} x \frac{22}{7} x (13)^{2}

                                        = \frac{20}{360} x x \frac{22}{7} x 169

                                         = 29.5079

The area of the sector (shaded section) is 29.51 m^{2}.

4 0
2 years ago
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