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xz_007 [3.2K]
3 years ago
15

Mr. Lebsock is 1 year younger than 10 times Addy’s age. If Mr. Lebsock is 29, write and solve equation to solve for Addy’s age.

Mathematics
1 answer:
Lina20 [59]3 years ago
5 0

Answer:

3

Step-by-step explanation:

29 = 10x - 1

+4

30 = 10x

30 divided by 10 = 3

3 = x

So Addy is 3.

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Need help multiplying -300 to N+M&M=10 for equation (1)​
xz_007 [3.2K]

Answer:

3.5 pounds of nuts; 6.5 pounds of M&Ms

Step-by-step explanation:

Let m represent the number of pounds of M&Ms to use. Then 10-m is the number of pounds of nuts, and the cost of the mix is ...

6·m + 3·(10-m) = 4.95·10 . . . . . cost = cost per pound times pounds

3m +30 = 49.5 . . . . . . simplify

3m = 19.5 . . . . . . . . . . . subtract 30

m = 6.5 . . . . . . . . . . . . . divide by 3

Then 10-m = 10-6.5 = 3.5.

The manager should use 3.5 pounds of nuts and 6.5 pounds of M&Ms in the mix.

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3 years ago
What is the range of f(x)?
adoni [48]

Answer:

best ans is { f(x)| –∞ < f(x) ≤ 4}

Step-by-step explanation:

usually to find the range of a fn, u need to see what the value can be. the graph show only a small range of x values. but u can see f(x) is definitely <u><</u>  4. so the ans is { f(x)| –∞ < f(x) ≤ 4}


6 0
4 years ago
Read 2 more answers
SO I NEED HELP ON THIS
erma4kov [3.2K]
Angle DAB is equivalent to angle DCB. The answer is 65°
8 0
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Prove that the following statements are false provide counter examples to disprove them: (1) If two angles have common vertex an
Andru [333]

Answer:

Examples to disprove them are as follows;

1) Angles of two different inscribed regular polygon in contact at their vertices

2) Angles on the opposite corners of a regular even sided polygon

Step-by-step explanation:

The statement to be disproved can be presented as follows;

1) ∠A and ∠B share a common vertex

2) The bisectors of ∠A and ∠B create one line then

∠A and ∠B are vertical, that is ∠A and ∠B are on the opposite sides of the point where two lines cross or ∠A = ∠B

Given that ∠A = Interior angle of a inscribed square = 90°

∠B = Interior angle of an inscribed equilateral triangle = 60°

Therefore the two circles can be arranged such that the line connecting the centers of both circles, are the bisectors of ∠A and ∠B

However, ∠A ≠ ∠B hence the two angles are not vertical QED

(2) The angles ∠A and ∠B where ∠A = ∠B are on the opposite corners of an even sided regular polygon are equal and their bisectors belong to the same line, however, it can be shown that ∠A and ∠B  are not vertical.

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3 years ago
Point-Slope form of the line that goes through (2, 7) with a slope of -4, please!
stellarik [79]

Answer:

y-7= -4(x-2)

Step-by-step explanation:

Y-Y1=M(X-X1) - point slope form equation.

Plug in each coordinate into their coresponding places, X1, Y1 and M (the slope).

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4 years ago
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