Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
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Answer: the answer is $ 17,349.21 APEX
Multiplying -15 by 60 yields -900, so the amount of water in the pool changes by -900 gallons in one hour.
the sequence is 4n-13, so substitute 107 into n and it will become 4(107)-13 =415
Answer:
(5 1/2 miles, $12.50)
Step-by-step explanation:
Looking at the graph, identify as best you can the coordinates of the point at which the two graphs cross. I read (5 1/2 miles, $12.50).
