47.72% people would obtain scores between 5 and 9.
For given question,
We have been given:
Mean, μ = 5
Standard Deviation, σ = 2
We are given that the distribution of score is a normal distribution.
We need to find the percentage of people who would obtain scores between 5 and 9.
We will use the formula for z-score.
= P(5 ≤ x ≤ 9)
= P()
= P(0 ≤ z ≤ 2)
= P(z ≤ 2) - P(z < 0)
= 0.9772 - 0.5
= 0.4772
= 47.72%
Therefore, 47.72% people would obtain scores between 5 and 9.
Learn more about the normal distribution here:
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Answer:
4.69 inches (2 decimal places)
Step-by-step explanation:
Refer to image attached to this answer:
Using Pythagoras Theorem:
-------------------------
Using Pythagoras Theorem,
<span>amount of water wasted varies directly with the amount of time
w varies directly with t
w = kt where k is constant of proportionality
1 = k × 4
k = 1/4 cup per minute
----</span>
Answer:
Expanded forms can be written like a sentence or stacked for readability
Step-by-step explanation:
Expanded Form:
5,000 + 300 + 20 + 5 = 5,325
(its like a sentence)
To find what 86% of 40 is, first convert 86% to a decimal, then multiply that decimal by 40.
86% = 0.86
0.86 • 40 = 34.4
So 86% of 40 is 34.4.