Answer:
Alicia is 18years
Quentin is 14years
Rosalyn is 16years
Step-by-step explanation:
Let the age of Alicia be x
Let the age of Quentin be y
Let the age of Rosalyn be z
If the sum of the siblings’ ages, in years, is 48 then;
x+y+z = 48.... 1
If Rosalyn is two years older than Quentin then;
z =y+2 ..... 2
Also if Quentin is four years younger than Alicia then;
y = x-4 ... 3
From 3:
x = y+4 ... 4
Substitute 2 and 4 into 1 to have:
y+4+y+y+2 = 48
3y + 6= 48
3y = 48-6
3y= 42
y = 14
Since x= y+4
x = 14+4
x = 18
Since z = y+2
z = 14+2
z = 16year
This means that;
Alicia is 18years
Quentin is 14years
Rosalyn is 16years
Find the area of the cone:
Area of cone: ⅓r^2h
⅓r^2h
= ⅓(3.5)^2(7)
= ⅓(12.25)(7)
= 1/3(85.75)
= 85.75/3
1/3 cup sloshed out:
(85.75/3 )/3
= 29.9 cubic cm
2x=16-2y
x=8-y
6(8-y)+4y=38
48-6y+4y=38
48-2y=38
-2y=-10
y=5
8-5=x
x=3 <-Answer
((n-2)×180)/n = 156
(n-2)×180=156n
24n =360
n =15
360/n =36
n = 10
a)15 b)10
Solve the problem then state if it's true or false- this is an order of operation problem. 3+2/3(3-X) this is the problem. Now distribute, 3+ 2/3(3)- 2/3(x)= 3+2- 2/3x so the final expression would be 5-2/3x I don't know about the <-7 part but that's the solution to the first one
