Answer:
The answer is below
Step-by-step explanation:
The standard form of the equation of an ellipse with major axis on the y axis is given as:

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²
Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37
Also, the foci is at (0,5) and (0, -5), therefore c = 5
Using c² = a² - b²:
5² = a² - 37²
a² = 37² + 5² = 1369 + 25
a² = 1394
Therefore the equation of the ellipse is:

Answer:0.14814814814, reduced your answer should be 0.148
Step-by-step explanation:
<span>se
sen x = 3/5 eleva ao quadrado ambos os lados
sen² x = (3/5)²
Tem que partir da relação fundamental
sen²x + cos²x = 1
(3/5)² + cos² x = 1
cos² x = 1 - (3/5)² = 16/25
cos x = V(16/25 = 4/5
b ) tg x = sen x / cos x = 3/5 / 4/5 = 3/5 * 5/4 = 3/4
c) cotg x = cosx / sen x = 1 / tgx = 1/ (3/4 = 4/3
d) sec x = 1/ cos x = 1 / 4/5 = 5/4
e) cossec x = 1 / sen x = 1/ 3/5 = 5/3
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edson</span>edson <span>· 9 anos atrás</span>