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Llana [10]
3 years ago
15

What makes the Earth go around the Sun?

Chemistry
1 answer:
vladimir1956 [14]3 years ago
3 0

Answer:

Just as the Moon orbits the Earth because of the pull of Earth's gravity, the Earth orbits the Sun because of the pull of the Sun's gravity. ... This happens because the Earth has a velocity in the direction perpendicular to the force of the Sun's pull.

Explanation:

You might be interested in
Calculate the mass of 6.9 moles of nitrous acid (HNO2). Explain the process or show your work by including all values used to de
AlexFokin [52]

Answer:- 324.3 grams.

Solution:-  We have been given with 6.0 moles of nitrous acid and asked to calculate it's grams. Moles to grams is a unit conversion and for doing this conversion we multiply the given moles by the molar mass of the compound.

Molar mass is the formula mass and to calculate this the atomic masses of each atom are multiplied by their respective subscripts that is the number of the atom in the compound .

For example, NO_2 has one nitrogen atom and one oxygen atom. So, the molar mass of this is = atomic mass of N + 2(atomic mass of O)

= 14 + 2(16)

= 14 + 32  

= 46 gram per mol

gram per mol is the unit of molar mass. So, the molar mass of NO_2 is 46 grams per mol.

Let's calculate the molar mass of nitrous acid using the same concept.

molar mass of [HNO_2 = 1 + 14 + 2(16)

= 1 + 14 + 32

= 47 grams per mol

Now, 6.9 moles of nitrous acid could easily be converted to grams as:

6.9molHNO_2(\frac{47g}{1mol})

= 324.3 g

Hence, the mass of 6.9 moles of nitrous acid is 324.3 grams.

6 0
3 years ago
How many grams is 5.4x10 to the 23 molecules of al2o3?
8090 [49]

Answer:

91.49 grams

Explanation:

No of molecules = no of moles × Avogadro's number

No of moles = No of molecules / Avogadro's number

Number of moles = 5.4×10^23/6.02×10^23

Number of moles = 0.897 moles of Al2O3

Number of moles = mass in gram / molar mass

Mass in gram = number of moles× molar mass

Mass in gram = 0.897× 102

91.49 grams

5 0
3 years ago
What type of heat transfer happens when warm air in
Mademuasel [1]
The answer is 1. Radiation
4 0
3 years ago
Read 2 more answers
What did the scientists who founded the royal society of London share with Lavoisier
morpeh [17]
They were natural philosophers that used experimentation to establish the cause effect relations and explanations, in an epoque when many "theories' were not supported by experiments but by some authority (antique philosophers like Aristoteles or the Catholic Church).
8 0
3 years ago
Read 2 more answers
Phosgene, COCl2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide w
jek_recluse [69]

The question is incomplete, here is the complete question:

Phosgene, COCl_2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide with chlorine:  

CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

The value of K_c for this reaction is 5.79 at 570 K. What are the equilibrium partial pressures of the three gases if a reaction vessel initially contains a mixture of the reactants in which p_{CO}=p_{Cl_2}=0.265atm and p_{COCl_2}=0.000atm ?

<u>Answer:</u> The equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

<u>Explanation:</u>

The relation of K_c\text{ and }K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p = Equilibrium constant in terms of partial pressure

K_c = Equilibrium constant in terms of concentration = 5.79

\Delta n_g = Difference between gaseous moles on product side and reactant side = n_{g,p}-n_{g,r}=1-2=-1

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

T = Temperature = 570 K

Putting values in above equation, we get:

K_p=5.79\times (0.0821\times 570)^{-1}\\\\K_p=0.124

We are given:

Initial partial pressure of CO = 0.265 atm

Initial partial pressure of chlorine gas = 0.265 atm

Initial partial pressure of phosgene = 0.00 atm

The given chemical equation follows:

                      CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

<u>Initial:</u>            0.265      0.265

<u>At eqllm:</u>        0.265-x    0.265-x        x

The expression of K_p for above equation follows:

K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}

Putting values in above equation, we get:

0.124=\frac{x}{(0.265-x)\times (0.265-x)}\\\\x=0.0082,8.59

Neglecting the value of x = 8.59 because equilibrium partial pressure cannot be greater than initial pressure

So, the equilibrium partial pressure of CO = (0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of Cl_2=(0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of COCl_2=x=0.008atm

Hence, the equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

6 0
3 years ago
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