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nika2105 [10]
3 years ago
11

How many moles are in 1.35 x10^23 representative particles of Fluorine?

Chemistry
2 answers:
Scorpion4ik [409]3 years ago
8 0
Atomic weight of fluorine is 19 g/mol.

We know that, 1 mol (19 g) of Fluorine will have Avagadro number (6.022 X 10^23) of Fluorine atoms 

Thus, we have 6.022 X 10^23 atoms of F ≡ 19 g of F
Therefore, 1.35 x10^23 atoms of F ≡ 4.259 g of F

Now, 19 g of Fluorine ≡ 1 mole
∴, 4.259 g of Fluorine ≡ 0.224 mole 

Answer: 0.224 <span>moles are in 1.35 x10^23 representative particles of Fluorine</span>
DochEvi [55]3 years ago
4 0
<span>Answer: 0.224 moles


Explanation:


1) Avogadro's number is 1 mol = 6.022 x 10²³, which means that there are 6.022 x 10²³ particles in 1 mol.


2) Divide the number of of particles by Avogadro's number to find how many moles that is:
</span><span />

<span>(1.35x10²³ / (6.022x10²³) = 0.224 moles</span>


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4 0
3 years ago
A 15.00-mL sample of an NaOH solution of unknown concentration requires 17.88 mL of a 0.1053 M H2SO4 M solution to reach the equ
Anastasy [175]

Answer:

The concentration of the NaOH solution CB = 0.251 M

Explanation:

The balanced equation of reaction is:

H2SO4 + 2NaOH ===> Na2SO4 + 2H2O

Using titration equation of formula

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)

NB is the number of mole of base = 2 (from the balanced equation of reaction)

CA is the concentration of acid = 0.1053 M

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Substituting

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6 0
4 years ago
Radioactive americium-241 is used in household smoke detectors and in bone mineral analysis.
Varvara68 [4.7K]

Answer:

Electrons- 95

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Neutrons-146

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4 0
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That's all I'm gonna do so yeah.

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So I hope you get it, I'm gonna let you do the rest.

4 0
2 years ago
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