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Anni [7]
2 years ago
15

PLEASE GELP WITH ALGEBRA Given the function below find f(-2). f(x) = x^2 – 3x + 5

Mathematics
2 answers:
Alborosie2 years ago
7 0

Answer:

20

Step-by-step explanation:

Tpy6a [65]2 years ago
7 0

Answer:

B) 15

Step-by-step explanation:

f(x)=x^2-3x+5

f(-2)=(-2)^2-3(-2)+5

f(-2)=4-(-6)+5

f(-2)=4+6+5

f(-2)=10+5

f(-2)=15

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What is the first step in solving the equation?<br><br> 14 = -2m
ollegr [7]

Answer:

first you need to divide each side by -2

Step-by-step explanation:

start with dividing by -2, then you are left with -7 = m which is the answer.

7 0
2 years ago
Paul bags of raisin bars in a pan shaped like a rectangle or prism the volume of the pan is 252 in.³ the length of the pants 12
e-lub [12.9K]

Answer:

The height of the pan is 2 inches.

Step-by-step explanation:

Given : Paul bags of raisin bars in a pan shaped like a rectangle or prism the volume of the pan is 252 in.³ the length of the pants 12 inches and it's with is 10\frac{1}{2} inches.

To find : What is the height of the pan ?

Solution :

The volume of a rectangle or prism is

V=l\times w\times h

Where, l=12 inches is the length

w=10\frac{1}{2} inches is the width

V=252 in.³ is the volume

h is the height

Substitute the value,

252=12\times 10\frac{1}{2}\times h

252=12\times \frac{21}{2}\times h

h=\frac{252\times 2}{12\times 21}

h=2

Therefore, the height of the pan is 2 inches.

7 0
3 years ago
The perimeter of a rectangle is given by P equals 2 l plus 2 w. Find the width of a rectangle whose length is 35 and perimeter i
maks197457 [2]
2l + 2w = P
l = 35,  P = 84,  w=?

2*35 + 2*w = 84
70 + 2w = 84
2w = 84 - 70
2w = 14
w = 14/2
w = 7 in
5 0
3 years ago
The one I’m pointing to
sveticcg [70]

Answer: hope that helps

Step-by-step explanation: 128 divided by 640 x 100 = 20%

4 0
3 years ago
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0
3 years ago
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