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Salsk061 [2.6K]
2 years ago
15

Chester's dog Tab will not go into the flower garden because he gets shocked by the electric fence each time. What would be the

conditioned stimulus (CS)? O The sight of Chester O The flowers and fence O Fear from being shocked O The shock​
Physics
1 answer:
Alex73 [517]2 years ago
6 0

Given what we know, we can confirm that the conditioned stimulus for the

dog to not run into the flower garden would be the shock experienced the previous times that he entered the garden.

<h3>What is a conditioned stimulus?</h3>
  • This is a response that occurs at an almost subconscious level, generated through previous experience.
  • It is a stimulus that has affected our response to a situation through repetitive conditioning.
  • In this situation, the electric shock has served as the conditioned stimulus for Chester's dog, tab.

Therefore, given that a conditioned stimulus is one that through repetition has taught the individual what actions to perform or avoid, we can confirm that the electric shock suffered by the dog the previous times he attempted to enter the garden has served as the conditioned stimulus in this situation.

To learn more about conditioned stimulus visit:

brainly.com/question/24868138?referrer=searchResults

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A person has legs of length L = 1.10 m. (a) If the maximum angle between the legs during walking is ϕ = 50o , what is the person
vampirchik [111]

Answer:

a). Maximum Length L=0.929m

b). T=0.83 Hz or 1.2s

c). Longer, the effortless waling T=2.1 Hz or t=0.475s

d). t=1.2s V=0.774 \frac{m}{s}

t=0.475s V=1.95 \frac{m}{s}

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angle=50

the step that give the person forms a triangle whose two sides are known and the angle that forms between them, then using trigonometry as the image

Divide the original triangle in two and form a right triangle so the angle is 25 and the L is hypotenuse and the opposite is the step length

a).

sin(\alpha) =\frac{op}{h}

op=h*sin(\frac{\alpha }{2})\\ op=1.1m*sin(\frac{50}{2})\\op=0.464m

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period=T

T=\frac{1}{time}=\frac{1}{t}\\ T=\frac{1}{1.2s}\\T=0.83 s^{-1}\\ T=0.83Hz

c).

T1=2\pi *\sqrt{\frac{L}{g}} \\T1=2\pi *\sqrt{\frac{1.1m}{9.8\frac{m}{s^{2}}}}\\ T1=2.1 Hz

The period is the inverse of the time of the motion so, the T1 is faster that the T because

t=\frac{1}{T1}=t= \frac{1}{2.1}=0.47s

d).

The speed is the relation between the distance with time so:

Vt=\frac{0.928m}{1.2s} \\Vt=0.773 \frac{m}{s} \\Vt=\frac{0.928m}{0.475s} \\Vt=1.953 \frac{m}{s}

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