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Sphinxa [80]
3 years ago
14

Describe an example of acceleration and explain how velocity is changing.

Physics
2 answers:
Mariulka [41]3 years ago
4 0

Answer:

A car speeding up.

Explanation:

sveticcg [70]3 years ago
4 0

Answer:

Ok

Explanation:

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meriva

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battery iron wire

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Comment l'azote entre dans l'atmosphère
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shark puppet

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8 0
3 years ago
A student of weight 678 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude
baherus [9]

Answer:

(a) Magnitude of seat force at lowest point = 678 + 92 = 770

(b) Force exerted by the seat (highest point)  = 310 N

(c) Force exerted by seat (lowest point) = 1046 N

Explanation:

At the highest point the magnitude of force by the seat = 586 N

The weight of the student = 678 N

Thus, at the highest point, the difference in this force is due to the centrifugal force acting on the boy. This can be calculated as follows:

Centrifugal Force = 678 - 586 = 92 N

(a) The magnitude of force on the student by the seat at the lowest point will have to appose both the student's weight and centrifugal force acting towards the ground. This would mean:

Magnitude of seat force at lowest point = 678 + 92 = 770 N

(b) If the wheel's speed is doubled, the centrifugal force will change accordingly. The equation of centrifugal force is given below:

F = m * v^2 / r

We can see from this that the force is directly proportional to the square of the velocity. So if the velocity is doubled, the centrifugal force increases four times.

So at the highest point the centrifugal force will decrease the force of weight acting on the seat. The seat force would then be:

Force exerted by the seat = Weight - Centrifugal force

Force exerted by the seat = 678 - (4 * 92)

Force exerted by the seat (highest point)  = 310 N

(c) The force exerted by the seat at the lowest point will be the centrifugal force plus the weight.

This is:

Force exerted by seat = Centrifugal force + Weight

Force exerted by seat = (4 * 92) + 678

Force exerted by seat (lowest point) = 1046 N

5 0
3 years ago
The standard molar heat of vaporization for water is 40.79 kj/mol. How much energy would be required to vaporize 4.72 x 10^10 mo
stellarik [79]
(5.81 x 10^10 molecules) / (6.022 x 10^23 molecules/mol) x (40.79 kj/mol) = 3.94 x 10^-12 kj
7 0
3 years ago
2. If an em' of Hg weighs 13.6 g, what is the mass of a cylinder of: Sem and height 20 Cm
Yuri [45]

Answer:

Let the mass of mercury  m= 13.6 gm and volume be V=1cm3.

Now change in volume when it is heated upto 50oC,

ΔV=VαΔT

ΔV=1×1.82×10−4×50

ΔV=91×10−4cm3 

New volume V1=V+ΔV=1.0091cm3

New density ρ=V1m=1.009113.6=13.48gcm−3

Explanation:

Mark me as a brainliest please

8 0
2 years ago
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