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Gala2k [10]
3 years ago
14

What 3 words complete the sentence?A moving object always has energy in its​

Physics
1 answer:
Arte-miy333 [17]3 years ago
7 0
Moving object and energy
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A small object with momentum 7.0 kg∙m/s approaches head-on a large object at rest. The small object bounces straight back with a
EastWind [94]

Answer:

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

Explanation:

Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:

p_{S,1}+p_{B,1} = p_{S,2}+p_{B,2} (1)

Where:

p_{S,1}, p_{S,2} - Initial and final momemtums of the small object, measured in kilogram-meters per second.

p_{B,1}, p_{B,2} - Initial and final momentums of the big object, measured in kilogram-meters per second.

If we know that p_{S,1} = 7\,\frac{kg\cdot m}{s}, p_{B,1} = 0\,\frac{kg\cdot m}{s} and p_{S, 2} = 4\,\frac{kg\cdot m}{s}, then the final momentum of the big object is:

7\,\frac{kg\cdot m}{s} + 0\,\frac{kg\cdot m}{s} = 4\,\frac{kg\cdot m}{s}+p_{B,2}

p_{B,2} = 3\,\frac{kg\cdot m}{s}

The magnitude of the large object's momentum change is:

p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}-0\,\frac{kg\cdot m}{s}

p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

4 0
3 years ago
Is there a formula for the 2nd Law of Therodynamics, is so name it?
IrinaK [193]

∆S>_closed integral of dQ/T

There are many equations for different situations of entropy but this is a general one

8 0
4 years ago
Un vehículo parte del reposo y acelera constantemente a 6 m/s2
grin007 [14]
Iskkkkkkkkkkkkkkkkmknnnn
4 0
3 years ago
If you walk 3 meters north and then 4 meters west, what is the magnitude of your displacement?
ankoles [38]
S^2=3^2+4^2
S^2=9+16
S^2=25
S=√25
S=5m
7 0
3 years ago
The drift speed in a copper wire is 4.08 × 10-5 m/s for a typical electron current. Calculate the magnitude of the electric fiel
jeka94

Answer:

9.07 x 10^-3 N/C

Explanation:

The mobility of electrons is defined as the ratio of drift velocity to the applied electric field.

Vd = 4.08 x 10^-5 m/s

Mobility = 4.5 x 10^-3 m/s

Let the electric field is E.

Mobility = Vd / E

E = Vd / mobility

E = 4.08 x 10^-5 / (4.5 x 10^-3)

E = 9.07 x 10^-3 N/C

6 0
3 years ago
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