Answer:
The angle's rate of change is: -0.125 (degree/feet).
Explanation:
In this case of problem we need to find the angle's rate (α) of change when x=6 ft. First we need to relate (α) with x and y and the expression that do it is:
where (α) is the angle between the ladder and the ground, x is the horizontal distance and y the vertical distance, now we need to have the variable y at function of x, so we can do it using the Pythagorean theorem and gets:
solving for y(x) we get:
. Replacing all we have got in the first equation:
. Finally we derivate this equation at function of variable x and gets this result:
evaluating at x=6 ft we get: -0.125(degree/feet). The negative signal means that the angle is decreasing.
The answer for this question is negative externality
Complete Question:
A 10 kg block is pulled across a horizontal surface by a rope that is oriented at 60° relative to the horizontal surface.
The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by the tension in the rope if the block when the block is 5 m away from its starting point? The coefficient of kinetic friction between the block and the floor is 0.2 and you may assume that the block starting at rest.
Answer:
Power = 54.07 W
Explanation:
Mass of the block = 10 kg
Angle made with the horizontal, θ = 60°
Distance covered, d = 5 m
Tension in the rope, T = 40 N
Coefficient of kinetic friction, 
Let the Normal reaction = N
The weight of the block acting downwards = mg
The vertical resolution of the 40 N force, 





Power, 

Answer:
The additional trials needed is 48 trials
Explanation:
Given;
initial number of trials, n = 16 trials
the standard deviation, σ = 0.24 s
initial standard error, ε = 0.06 s
The standard error is given by;

To reduce the standard error to 0.03 s, let the additional number of trials = x

Therefore, the additional trials needed is 48 trials.
Answer:
m,lkj,mkn,njn
Explanation:because she is telling you to do a project