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sweet [91]
4 years ago
11

A tire hanging from a tree is at rest. The force of gravity is pulling down on the tire. Another force, called tension, is pulli

ng up on the tire. Tension is the pulling force that is transferred along the length of a string or rope. If the force of tension is equal to the force of gravity, then what will happen to the tire?
Physics
2 answers:
masha68 [24]4 years ago
8 0

the answer is that the tire will remain rest, An object that is at rest will stay at rest until an unbalanced force acts on it. The two forces acting on the tire are balanced because they are equal in magnitude and opposite in direction. Therefore, the tire will remain at rest.

iren [92.7K]4 years ago
6 0

C. The tire will remain at rest

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a. No, typical small pickup truck springs are not large enough to compress 0.61{\rm m}.

Explanation:

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3 years ago
*photo attached* The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.67 m and 1.01 m, respectivel
stiks02 [169]

(a) The speeds of the tips of both rotors; main rotor <u>178.3 m/s</u> and  tail rotor <u>218.4 m/s</u>.

(b) The speed of the main rotor is <u>0.52</u> speed of sound, and the speed of the tail rotor is <u>0.64</u> speed of sound.

<h3>Linear speed of main motor and tail rotor</h3>

v = ωr

where;

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  • r is radius (m)

v(main rotor) = (444 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.67 m)

v(main rotor) = 178.3 m/s

v(tail rotor) = (4,130 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.01 m)

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<h3>Speed of the rotors with respect to speed of sound</h3>

% speed (main motor) = 178.3/343 = 0.52 = 52 %

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5 0
2 years ago
The force of gravity acting<br> on a child's mass on earth is 490 newtons. what's the child's mass?
UNO [17]
F = m • a

What we know:
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- Force: 490 N

Equation derived:
m = F/a
m = 490/9.8
= 50 kg
6 0
3 years ago
Read 2 more answers
Four forces act on bolt A as shown; F1 150N, F2 80N, F3 110N and F4 100N. Determine the magnitude and direction of the resultant
netineya [11]

Complete Question

The  complete question(reference (chegg)) is shown on the first uploaded image

Answer:

The magnitude of the resultant force is  F  =  199.64 \ N

The  direction of the resultant force is  \theta  =  4.1075^o from the horizontal plane

Explanation:

Generally when resolving force, if the force (F )is moving toward the angle then the resolve force will be  Fcos(\theta ) while if the force is  moving away from the angle  then the resolved force is  Fsin (\theta )

Now  from the diagram let resolve the forces to their horizontal component

    So

          \sum F_x  =  150 cos(30) + 100cos(15) -80sin (20)

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Now  resolving these force into their vertical component can be mathematically evaluated as

         \sum  F_{y}  =  150 sin(30) - 100sin(15) -110 +80 cos(20)

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substituting values

        F  =  \sqrt{199.128^2 + 14.3^2}

        F  =  199.64 \ N

The  direction of the resultant force is  evaluated as

       \theta  =  tan^{-1}[\frac{F_y}{F_x} ]

substituting values

       \theta  =  tan^{-1}[\frac{ 14.3}{199.128} ]

       \theta  =  4.1075^o from the horizontal plane

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It will not explode since the mass of the cotton balls is so low but rather will most likely break the lock and hinges and come out.
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3 years ago
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