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sweet [91]
3 years ago
11

A tire hanging from a tree is at rest. The force of gravity is pulling down on the tire. Another force, called tension, is pulli

ng up on the tire. Tension is the pulling force that is transferred along the length of a string or rope. If the force of tension is equal to the force of gravity, then what will happen to the tire?
Physics
2 answers:
masha68 [24]3 years ago
8 0

the answer is that the tire will remain rest, An object that is at rest will stay at rest until an unbalanced force acts on it. The two forces acting on the tire are balanced because they are equal in magnitude and opposite in direction. Therefore, the tire will remain at rest.

iren [92.7K]3 years ago
6 0

C. The tire will remain at rest

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If a planet has the same mass as the earth, but has twice the radius, how does the surface gravity, g, compare to g on the surfa
shepuryov [24]

Answer:

The surface gravity g of the planet is 1/4 of the surface gravity on earth.

Explanation:

Surface gravity is given by the following formula:

g=G\frac{m}{r^{2}}

So the gravity of both the earth and the planet is written in terms of their own radius, so we get:

g_{E}=G\frac{m}{r_{E}^{2}}

g_{P}=G\frac{m}{r_{P}^{2}}

The problem tells us the radius of the planet is twice that of the radius on earth, so:

r_{P}=2r_{E}

If we substituted that into the gravity of the planet equation we would end up with the following formula:

g_{P}=G\frac{m}{(2r_{E})^{2}}

Which yields:

g_{P}=G\frac{m}{4r_{E}^{2}}

So we can now compare the two gravities:

\frac{g_{P}}{g_{E}}=\frac{G\frac{m}{4r_{E}^{2}}}{G\frac{m}{r_{E}^{2}}}

When simplifying the ratio we end up with:

\frac{g_{P}}{g_{E}}=\frac{1}{4}

So the gravity acceleration on the surface of the planet is 1/4 of that on the surface of Earth.

3 0
3 years ago
An important dimensionless parameter in certain types of fluid flow problems is the Froude number defined as V/√g.l where V is a
prohojiy [21]

Answer:

1.24611

Explanation:

V = Velocity = 10 ft/s

L = Length = 2 ft

g = Acceleration due to gravity = 32.2 ft/s²

Froude number is given by

Fr=\dfrac{V}{\sqrt{gL}}\\\Rightarrow Fr=\dfrac{10}{\sqrt{32.2\times 2}}\\\Rightarrow Fr=1.24611

Converting to SI units

10\ ft/s=10\times \dfrac{1}{3.281}

32.2\ ft/s^2=32.2\times \dfrac{1}{3.281}

2\ ft=2\times \dfrac{1}{3.281}

Fr=\dfrac{V}{\sqrt{gL}}\\\Rightarrow Fr=\dfrac{10\times \dfrac{1}{3.281}}{\sqrt{32.2\times \dfrac{1}{3.281}\times 2\times \dfrac{1}{3.281}}}\\\Rightarrow Fr=1.24611

The Froude number is 1.24611

The Froude number is equal. The Froude number is dimensionless as the units cancel each other. In order for this to happen the units used need to be consitent either imperial or SI.

7 0
2 years ago
Can molecules with double or triple bonds twist
stiks02 [169]

Answer:

No.

Explanation:

The only way a twist may be done is if the trans form of an alkene/alkyne is twisted into the cis form--only if/when the pi bond is brokwn.

6 0
2 years ago
A Martian rover found an interesting rock that could contain signs of what Mars was like long ago. It grabbed
kodGreya [7K]

Answer:

It would be PE=16kg * 9.8 m/s^2 * 1m = 160 J

Explanation:

The person who asked this question ended up answering his own question so I'm here to let you know all that the answer was founded by the person whos posted the question himself full credit goes to him :)

3 0
2 years ago
Calculate the following expression: 2.36 + 3.38 + 0.355 + 1.06 =
mario62 [17]

the answer wil be 2.36+3.38+0.355+1.06=7.155

5 0
2 years ago
Read 2 more answers
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