Supplementary angles add up to 180
So
I tho l it’s B
You can rearrange the equation as follows:
![x^2 = -24](https://tex.z-dn.net/?f=%20x%5E2%20%3D%20-24%20)
Using real numbers, it would be impossible for a square to be negative, but using imaginary numbers it is possible, since ![i^2 = -1](https://tex.z-dn.net/?f=%20i%5E2%20%3D%20-1%20)
So, since
, we know that
![(i\sqrt{24})^2 = i^2\cdot \sqrt{24}^2 = (-1)\cdot 24 = -24](https://tex.z-dn.net/?f=%20%28i%5Csqrt%7B24%7D%29%5E2%20%3D%20i%5E2%5Ccdot%20%5Csqrt%7B24%7D%5E2%20%3D%20%28-1%29%5Ccdot%2024%20%3D%20-24%20)
So, the solutions to the equations are
![x^2 = -24 \iff x = \pm\sqrt{-24} = \pm i \sqrt{24}](https://tex.z-dn.net/?f=%20x%5E2%20%3D%20-24%20%5Ciff%20x%20%3D%20%5Cpm%5Csqrt%7B-24%7D%20%3D%20%5Cpm%20i%20%5Csqrt%7B24%7D)
Answer:
b. There is sufficient evidence to indicate that exactly 65% of all e-commerce shoppers fail in their attempts to purchase merchandise on-line because Web sites are too complex.
Step-by-step explanation:
Not significant,accept null hypothesis that population proportion = 0.65
When we accept the null hypothesis that P= 0.65
Then only option b is correct which states that there is sufficient evidence to support that population proportion is exactly 0.65 .
1) We obtain a P - value of 0.0522 which is greater than 0.5 indicating that the null hypothesis is not rejected.
The rejection region for this right-tailed test is z > 1.64
2) Test Statistics
z= p`-p0/ sqrt(p0(1-p0)/n)
The z-statistic is computed as follows:
z= 0.75-0.65/ √(0.65*0.35)60
z= 1.624
3) Decision about the null hypothesis
Since it is observed that z = 1.624 is less than z ∝=1.64, it is then the null hypothesis is not rejected.