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Ipatiy [6.2K]
2 years ago
6

Lindsay borrowed ₱120,000 in a bank for a year. If she paid ₱139,290.54 on the maturity date, at what rate of interest, compound

ed monthly, did she pay?
Mathematics
1 answer:
Yuki888 [10]2 years ago
5 0

She paid the loan at a 15% rate of interest.

Given that Lindsay borrowed $ 120,000 in a bank for a year, if she paid $ 139,290.54 on the maturity date, to determine at what rate of interest, compounded monthly, did she pay, the following calculation must be performed:

  • 120,000 x (1 + X / 12) ^ 12 = 139,290.54
  • (1 + X / 12) ^ 12 = 139,290.54 / 120,000
  • 1 + X / 12 = 12√1.1607545
  • X / 12 = 1,012 - 1
  • X = 15

Therefore, she paid the loan at a 15% rate of interest.

Learn more about interest in brainly.com/question/25725602

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Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

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Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

z=\frac{x-\mu}{\sigma}

Plug in the values and solve for 'z'. This gives,

z=\frac{2.33-1.75}{0.22}=2.64

So, the z-score of the distribution is 2.64.

Now, we need the probability P(x\geq 2.33 )=P(z\geq  2.64).

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

P(z\geq  2.64)=1-0.9959=0.0041=0.41\%

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0
3 years ago
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alisha [4.7K]

Answer:

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Step-by-step explanation:

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Answer:

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