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3 years ago

Determine whether the polynomial is a difference of squares and if it is, factor it. y2 – 16

Mathematics

2 answers:

luda_lava [24]3 years ago

6 0

I think it’s not a different of squares because when u factor it =2(y-8)

Kryger [21]3 years ago

5 0

(y – 4)(y + 4) it is a difference this is it. I did the test just a second ago.

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Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

3 years ago

Tim has to cover 3 tanks completley with paint.

bija089 [108]

answer:

<h3>Total surface area of 3 tanks=34.3 m^2</h3><h3>7 tins of paint are required.</h3>

Solution,

diameter of tank=1.4 m

Height of tank=1.9 m

Given tank has top and bottom 

Now, The total surface area of cylinder tank is given by:

 $tsa = 2\pi \: {r}^{2} + (2\pi \: r \: ) \times h$ 

r( radius of tank)=

 $\frac{diameter}{2} = \frac{1.4}{2} = 0.7 \: m$ 

h(height of tank)=1.9 m

TSA of 1 tank

=

 $2 \times 3.14 \times {(0.7)}^{2} + 2 \times 3.14 \times 0.7 \times 1.9 \\ = 11.435 \: {m}^{2}$ 

TSA Of 3 tanks

=

 $3 \times 11.435 \: {m}^{2} \\ = 34.3 \: {m}^{2}$ 

Given a tin of plate covers 5m^2 area.

No.of tins required:

1 tin 5m^2

x tin 34.3 m^2

 $5x = 34.3(cross \: multiplication) \\ or \: x = \frac{34.3}{5} \\ x = 6.86 \\ x = 7 \: tins$ 

therefore 7 tins are required.

Hope this helps...

Good luck on your assignment....

8 0

2 years ago

Is 3/10 equivalent to 9/30

NemiM [27]

Yes it is because if you multiply 3*3=9
then what you do on top you do on the bottom 10*3=30

3 0

3 years ago

Read 2 more answers

Will mark brainliest pls answer

alukav5142 [94]

Y =0.5x +2 The y-intercept is found by the coordinates (0,2) and the change is 0.5

4 0

2 years ago

PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEE HELP ME. IF I PASS THIS I GET TO GO TO DISNEY WORLD.

Vera_Pavlovna [14]

Answer:

I think it would be C

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers