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AlekseyPX
3 years ago
13

18 - 2 x (4 + 3) Pls help

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer: 4

Step-by-step explanation:

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Put a digit in the gap, such that the answer is a whole number<br><br> 10x+11=144...
d1i1m1o1n [39]

Answer:

the answer is 1

Step-by-step explanation:

If you do 1441-11 you get 1430.

no other number gives you 0.

8 0
3 years ago
Can someone help me with this.
kodGreya [7K]
  1. Answer:  1/24  1/3

Step-by-step explanation:

6 0
2 years ago
Jamie took an 8-week keyboarding class. At the end of each week, she took a test to find the number of words she could type per
Bingel [31]
She improved about 4.3 words per min each week
6 0
3 years ago
Let: f(x)=x+1 and g(x)=x^2-2 <br><br> find: f(x)•g(x)
lesya692 [45]

Answer: x3+x2−2x−2

Step-by-step explanation: Use the given functions to set up and simplify f ( x ) ⋅ ( g ( x ) ) .

Brainliest or a thank you please! have a great day/night

3 0
3 years ago
Limit as x approaches infinity: 2x/(3x²+5)
Nonamiya [84]
\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\implies \cfrac{\lim\limits_{x\to \infty}~2x}{\lim\limits_{x\to \infty}~3x^2+5}

now, by traditional method, as "x" progresses towards the positive infinitity, it becomes 100, 10000, 10000000, 1000000000 and so on, and notice, the limit of the numerator becomes large.

BUT, notice the denominator, for the same values of "x", the denominator becomes larg"er" than the numerator on every iteration, ever becoming larger and larger, and yielding a fraction whose denominator is larger than the numerator.

as the denominator increases faster, since as the lingo goes, "reaches the limit faster than the numerator", the fraction becomes ever smaller an smaller ever going towards 0.

now, we could just use L'Hopital rule to check on that.

\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}~\cfrac{2}{6x}

notice those derivatives atop and bottom, the top is static, whilst the bottom is racing away to infinity, ever going towards 0.
5 0
3 years ago
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