Answer:
3 2/5
5 2/5
5 1/3
3 1/3
4 2/7
6 3/4
Step-by-step explanation:
27÷5= 5 2/5 ( 5 with remainder 2. Also written as 2/5...so 5 2/5)
Answer:
The second choice: graph begins in the second quadrant near the axis and increases slowly while crossing the ordered pair 3, 1. The graph then begins to increase quickly throughout the first quadrant.
Explanation:
1) As per the set of choices, the function is:

2) Therefore it is an exponential function with these characteristics:
- Since, the bases is greater than 1 (2), the function is growing in all the domain.
- The domain is all real numbers (- ∞, ∞).
- To know where the function starts, calculate the limit of f(x) as x trends to negative infinity:

That means that the range is y > 0, and so the graph starts in the second quadrant.
- You can find the y-intersection making x = 0, which is 2⁰ ⁻ ³ = 2 ⁻³ = 1/8 = 0.25. So, the graph cross the y axis at y = 0.25.
- That tells you, that the function increases slowly, at least, until that point (0, 0.25).
- The other bullet point is when x = 3: 2 ³ ⁻ ³ = 2⁰ = 1. Therefore, the graph passes through the point (3, 1).
- From that point, the function starts to increase rapidly (since it is exponential).
- Those are the characteristics given by the second choice: graph begins in the second quadrant near the x-axis and increases slowly while crossing the ordered pair 3, 1. The graph then begins to increase quickly throughout the first quadrant.
You surely will find useful to watch the graph that I have attached.
Answer:
17, 50, 9
Step-by-step explanation:
Hello
We already know the values of x and y, 5 and 2.
All we have to do to figure out a, b, and c, is to plug in those known values.
a) 3x + y
Let's plug in x and y as 5 and 2
3(5) + 2
15 + 2
17
b) 2x^2
2(5)^2
2(25)
50
c) (x - y)^2
(5 - 2)^2
3^2
9
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
To construct an angle MNT congruent to angle PQR:
Steps to construct an angle MNT:
Step 1: Use a compass to draw an arc from point Q which intersects the side PQ at point A and the side QR at point B.
Step 2: Draw a segment NT and use the same width of the compass to draw an arc from point N which intersects the segment NT at a point X.
Step 3: Adjust the width of the compass to AB, and draw an arc from point X such that it intersects the previous arc drawn from N in a point Y.
Step 4: Join points N and Y using a straightedge.
Step 5: Angle MNT is the required angle congruent to angle PQR.