Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
Ax^2+bx=c
REMEMBER THIS
ok
first, make sure that a is 1
done
now take 1/2 of b and square it
-18/2=-9, (-9)^2=81
add that to both sides
x²-18x+81=19+81
x²-18x+81=99
factor perfect square
(x-9)²=100
square root both sides
don't forget positive and negative root
x-9=10
x-9=-10
ad 9 to both sides
x=19
x=-1
answer is -1; 19
2nd choice is answer
*Yes, B, C, and D are correct. -15, -10.5, and -7.5 are solutions to x<-7*...........................
......................................................................................................................................
*8y – 24 > –16.............................................................................................................
8y>8 ADD 24 to both sides .......................................................................................
y>1 so C. divide both sides by 8.................................................................................
It is not A because the opposite of subtracting 24 is adding 24. So you add 24 to both sides to undo the subtraction. -16+24=8 Then you divide both sides by 8, which gives you y>1. I think you probably subtracted 24 from -16 instead of adding it.*.........................................
......................................................................................................................................
*I'm not sure what to make of the third one, is that a number line or...?*...............................
......................................................................................................................................
*- t/5 ≥15 ........................................................................................................................
-t ≥ 75 MULTIPLY both sides by 5....................................................................................
t ≤ -75 divide both sides by -1, and flip the sign, because when dividing an inequality by a negative number you must flip the sign..............................................................................
So A would be correct. ....................................................................................................
I believe if you divided the 15 by 5 and didn't flip the sign you would get D.*.........................
Also, sorry, my enter key isn't working right, so it's all scrunched together.
Answer:
under 50%
Step-by-step explanation:
i forgot how to get the excat percentage sorry :(