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AlladinOne [14]
2 years ago
14

A sample of 300 subscribers to a particular magazine is selected from a population frame of 9,000 subscribers. If, upon examinin

g the data, it is determined that no subscriber had been selected in the sample more than once:________.
A. the sample could not have been random
B. the sample may have been selected without replacement or with replacement
C. the sample had to have been selected without replacement
D. the sample had to have been selected with replacement
Mathematics
1 answer:
professor190 [17]2 years ago
3 0

Answer:

C

Step-by-step explanation:

You might be interested in
Please someone helpppp ):
skad [1K]

Answer:

  70 -20x = 60 -15x

Step-by-step explanation:

The amount of money left on Josh's card is ...

  70 -20x

The amount of money left on Jessica's card is ...

  60 -15x

These amounts are the same when ...

  70 -20x = 60 -15x

_____

<em>Additional comment</em>

The solution to this equation is ...

  10 = 5x   ⇒   x = 2 . . same amount after purchase of 2 pizzas

3 0
2 years ago
You want to purchase a house in 10 years. You estimate the cost will be $184,500.00. You want to make a 20% down payment and pay
Ilia_Sergeevich [38]
Use the formula of the future value of annuity ordinary and solve for pmt
First deducted the amount of down payment
184,500−184,500×0.20=147,600

Pmt=147,600÷(((1+0.085
÷12)^(12×10)−1)÷(0.085÷12))
=784.53 per month
5 0
3 years ago
Every day your friend commutes to school on the subway at 9 AM. If the subway is on time, she will stop for a $3 coffee on the w
Shtirlitz [24]

Answer:

1.02% probability of spending 0 dollars on coffee over the course of a five day week

7.68% probability of spending 3 dollars on coffee over the course of a five day week

23.04% probability of spending 6 dollars on coffee over the course of a five day week

34.56% probability of spending 9 dollars on coffee over the course of a five day week

25.92% probability of spending 12 dollars on coffee over the course of a five day week

7.78% probability of spending 12 dollars on coffee over the course of a five day week

Step-by-step explanation:

For each day, there are only two possible outcomes. Either the subway is on time, or it is not. Each day, the probability of the train being on time is independent from other days. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

The probability that the subway is delayed is 40%. 100-40 = 60% of the train being on time, so p = 0.6

The week has 5 days, so n = 5

She spends 3 dollars on coffee each day the train is on time.

Probabability that she spends 0 dollars on coffee:

This is the probability of the train being late all 5 days, so it is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.6)^{0}.(0.4)^{5} = 0.0102

1.02% probability of spending 0 dollars on coffee over the course of a five day week

Probabability that she spends 3 dollars on coffee:

This is the probability of the train being late for 4 days and on time for 1, so it is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.6)^{1}.(0.4)^{4} = 0.0768

7.68% probability of spending 3 dollars on coffee over the course of a five day week

Probabability that she spends 6 dollars on coffee:

This is the probability of the train being late for 3 days and on time for 2, so it is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{5,2}.(0.6)^{2}.(0.4)^{3} = 0.2304

23.04% probability of spending 6 dollars on coffee over the course of a five day week

Probabability that she spends 9 dollars on coffee:

This is the probability of the train being late for 2 days and on time for 3, so it is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456

34.56% probability of spending 9 dollars on coffee over the course of a five day week

Probabability that she spends 12 dollars on coffee:

This is the probability of the train being late for 1 day and on time for 4, so it is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592

25.92% probability of spending 12 dollars on coffee over the course of a five day week

Probabability that she spends 15 dollars on coffee:

Probability that the subway is on time all days of the week, so P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.6)^{5}.(0.4)^{0} = 0.0778

7.78% probability of spending 12 dollars on coffee over the course of a five day week

8 0
3 years ago
Whats the linear function in slope intercept form :<br> -6x+9y=54
babunello [35]
9y  = 6x + 54
divide through by 9:-
y = 6/9y + 54/9


y = 2/3 x  + 6 <---- answer
4 0
3 years ago
Read 2 more answers
What is the multiplicative rate of change of the function shown on the graph? Express your answer in decimal form. Round to the
allsm [11]
In linear models there is a constant additve rate of change. For example, in the equation y = mx + b, m is the constanta additivie rate of change.


In exponential models there is a constant multiplicative rate of change.


The function of the graph seems of the exponential type, so we can expect a constant multiplicative exponential rate.


We can test that using several pair of points.


The multiplicative rate of change is calcualted in this way:

 [f(a) / f(b) ] / (a - b)

Use the points given in the graph: (2, 12.5) , (1, 5) , (0, 2) , (-1, 0.8)

[12.5 / 5] / (2 - 1) = 2.5


[5 / 2] / (1 - 0) = 2.5


[2 / 0.8] / (0 - (-1) ) = 2.5


Then, do doubt, the answer is 2.5





6 0
3 years ago
Read 2 more answers
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