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sweet-ann [11.9K]
2 years ago
13

What is the range of the function?

Mathematics
1 answer:
Eduardwww [97]2 years ago
6 0

Answer:

C.

Step-by-step explanation:

The range of a function is the complete set of all possible resulting values of the function

which is here just (3 , 9 , 12)

so the choice is C.

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What is the answer to the following equation 13pt13-p
xeze [42]
You have to distribute it.
EXPLANATION:

13 pt 13-p
13-13
0 pt-p
-p-0
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14 pt
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8 0
3 years ago
Explain how to solve the equation 2(4x-11) +9=19
xxMikexx [17]
X=4, first you distribute the 2 to both 4x and -11 which leaves you with 8x-22+9=19 next you add -22 with 9 which leaves you -13 the eqation now at 8x-13=19 so now you add 13 to both sides now youre left with 8x=32. Now the last step is to divide 8 on both sides. so that gives you the answer or X=4
6 0
3 years ago
Which of these numbers is in the solution set of x + 5 = 15? A. 10 B. 3 C. 20 D. 11
stealth61 [152]

Answer:

A

Step-by-step explanation:

10 + 5 = 15

6 0
3 years ago
Read 2 more answers
(m) रेखीय फलन (Linear function)
Law Incorporation [45]

Answer:

???????????????????????????????

Step-by-step explanation:

5 0
3 years ago
Can someone help me please?
Elena-2011 [213]
<h3>Answer:  4368 square feet</h3>

======================================================

Explanation:

Check out the diagram below

I drew a rectangle with dimensions 56 ft by 78 ft.

Then I broke up the 56 into 50+6, and I broke up the 78 into 70+8

The reason for this is because it's fairly easy to multiply the areas of each smaller rectangle at this point

  • In the upper left corner, we have an area of 50*70 = 3500. Note how this is basically 5*7 = 35, but we tack on the two zeros (from 50 and 70 combined)
  • In the upper right corner, we have an area of 70*6 = 420
  • In the lower left corner, we have an area of 50*8 = 400
  • In the lower right corner, we have an area of 6*8 = 48

Add up all the areas found: 3500+420+400+48 = 4368

As a way to check, using your calculator shows that 56*78 = 4368

8 0
2 years ago
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