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Mars2501 [29]
2 years ago
10

Solve for q using both equation 1 and 2 question in pic

Mathematics
1 answer:
galina1969 [7]2 years ago
4 0

Answer:

p=1/8     q=3/4

Step-by-step explanation:

-2p+7q=5

-6p+35q=51/2

cancel out a variable

(-5)(-2p+7q=5)

-6p+35q=51/2

10p-35q=-25

-6p+35q=51/2  =

4p=1/2

4p/4=1/2  /4

p=1/8

substitute p=1/8 into one of the equation to find q

-2p+7q=5

-2(1/8)+7q=5

-1/4+7q=5

7q=5+1/4

7q=21/4

q= 21/4  /7

q=3/4

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1) What is the solution of the given system?
m_a_m_a [10]

Answer:

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2


Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

------------------

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5


2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23


Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128


Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115


Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

---------------------

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5





3 0
3 years ago
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