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Sveta_85 [38]
4 years ago
9

What’s the correct answer for this question?

Mathematics
1 answer:
lys-0071 [83]4 years ago
6 0

Answer:

C.

Step-by-step explanation:

1/2r = 2π/Cb

You might be interested in
Josephine has a rectangular garden with an area of 2x2
sergeinik [125]

Answer:

Fourth example, (2x - 3) and (x + 2), are possible dimensions

Step-by-step explanation:

Let's go through all the responses one by one;

First of all the area of the rectangular garden can be computed through length times width, such that:

(x^2 - 3) * (2) = 2x^2 + x - 6,

(2x + 3) * (x-2) = 2x^2 + x - 6,

(2x + 2) * (x-3) = 2x^2 + x - 6,

(2x - 3) * (x + 2) = 2x^2 + x - 6

Now in each of these examples, it should be that the products are equivalent to the area according to the length by width rule, so let's see which is truly the correct dimensions by justifying whether the product is truly equivalent to the area.

First example:

2 * (x^2 - 3) = 2x^2 - 6

Now 2x^2 - 6 ≠ 2x^2 + x - 6 so the first example is not a possibility,

Second example:

(2x + 3) * (x-2) = 2x^2- x - 6

Now 2x^2- x - 6 ≠ 2x^2 + x - 6 so the second example is not a possibility,

Third example:

(2x + 2) * (x-3) = 2x^2 - 4x - 6

Now 2x^2 - 4x - 6 ≠ 2x^2 + x - 6 so the third example is not a possibility,

Fourth example:

(2x - 3) * (x + 2) = 2x^2 + x - 6

Here 2x^2 + x - 6 = 2x^2 + x - 6 so the fourth example can act as possible dimensions

6 0
3 years ago
Read 2 more answers
Question #1<img src="https://tex.z-dn.net/?f=6%5Cgeq%20-4x-2" id="TexFormula1" title="6\geq -4x-2" alt="6\geq -4x-2" align="absm
natima [27]
X is greater than or equal to -2
5 0
4 years ago
If y = 9x − 7, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs?
Crazy boy [7]

Answer:

0,-7 8,567;7,57,6,6,6,6,6,78,3,5

8 0
3 years ago
Please answer!!!!!!!!!!!
irga5000 [103]

Answer:

i think its A

Step-by-step explanation:

7 0
3 years ago
(b) If a series follows geometric progression, show that the ratio of the sum of term to the sum from (n+1) term to (2n) term is
Nadusha1986 [10]

Proof with explanation:

We know that the sum of first 'n' terms of a Geometric progression is given by

S_{n}=\frac{a(1-r^{n})}{1-r}

where

a = first term of G.P

r is the common ratio

'n' is the number of terms

 Thus the sum of 'n' terms is

S_{n}=\frac{a(1-r^{n})}{1-r}

Now the sum of first '2n' terms is

S_{2n}=\frac{a(1-r^{2n})}{1-r}

Now the sum of terms from (n+1)^{th} to (2n)^{th} term is S_{2n}-S_{n}

Thus the ratio becomes

\frac{S_{n}}{S_{2n}-S_{n}}\\\\=\frac{\frac{a(1-r^{n})}{1-r}}{\frac{a(1-r^{2n})}{1-r}-\frac{a(1-r^{n})}{1-r}}\\\\=\frac{1-r^{n}}{r^{n}-r^{2n}}\\\\=\frac{1-r^{n}}{r^{n}(1-r^{n})}\\\\=\frac{1}{r^{n}}

5 0
3 years ago
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