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Scrat [10]
2 years ago
5

Which answer choice correctly represents 0.513333… ?A.B.C.D.

Mathematics
2 answers:
Zepler [3.9K]2 years ago
7 0
Abdc

I think so cuz I did this and got it right hopefully it is right good luck
Nady [450]2 years ago
7 0

Answer:

<h2>0.513333...=<u>0.513</u></h2>

Step-by-step explanation:

I don't see the choice.

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Jenny deposits $100 every month into her
serious [3.7K]

Answer:

$300

Step-by-step explanation:

y = 100x + 300

where X represents the amount of months.

6 0
3 years ago
In an engineering test, a rocket sled is propelled into a target. The sled’s distance d in meters from the target is given by th
creativ13 [48]
You're given d = 10
10 = -1.5t<span>2 = 110
</span>t^{2} = 220/3
since t \geq 0
t = \sqrt 220/3
I apologize if this is wrong!
6 0
3 years ago
4 movie tickets cost $48. At this rate with is the cost of 5 movie tickets
cupoosta [38]
60 dollars, because each movie ticket cost 12$.
4 0
3 years ago
Read 2 more answers
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
What is the exact value of cos 45° ?
Georgia [21]
Let the two sides of a right triangle be equal to one, which means that the hypotenuse is √2

Since cosa=adjacent side / hypotenuse

cos45=1/√2

We can rationalize the denominator by multiplying numerator and denominator by √2

√(2)/2

or if you prefer:  √(1/2)
3 0
3 years ago
Read 2 more answers
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