Answer:
6 root 2
Step-by-step explanation:
Pythagous Therom
A^2 = B^2 + C^2
B^2 = C^2 - A^2
B^2 = 36 - (2 Root 3)^2
B^2 = 24
B = 2 root 6
Base x Height / 2 for area of Triangle
2 root 3 x root 24 = 12 root 2
12 root 2 / 2 = 6 root 2
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ
Use the Sum/Difference Identities:
sin(α + β) = sinα · cosβ + cosα · sinβ
cos(α - β) = cosα · cosβ + sinα · sinβ
Use the Unit circle to evaluate: sin45 = cos45 = √2/2
Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ
Use the Pythagorean Identity: cos²Ф + sin²Ф = 1
<u />
<u>Proof LHS → RHS</u>
LHS: 2sin(45 + 2A) · cos(45 - 2A)
Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)
Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]
Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]
Distribute: cos²2A + 2cos2A·sin2A + sin²2A
Pythagorean Identity: 1 + 2cos2A·sin2A
Double Angle: 1 + sin4A
LHS = RHS: 1 + sin4A = 1 + sin4A 
Answer:
A: 1
B: 17
C: 26
D: 42
E: 57
Step-by-step explanation:
Answer:
proved
Step-by-step explanation:
plz mark me brainliest
Answer: 3/2a3
I can't properly write the answer sorry but it's the last one.