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Elena L [17]
3 years ago
11

5. The infographic suggests making small payments on your student loans even before they’re due, yet that won’t automatically ge

t you a credit card. What would be the benefit of making these early loan payments?
Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

It would be a pro

Step-by-step explanation:

Pay less over the life of the loan: Because your student loan, like most other debt, accrues interest when you carry a balance, it's cheaper if you pay off the loan earlier. It gives the debt less time to accumulate interest, which means that you'll pay less money in the long run.

Hope this helps.

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10) Find the Greatest Common Factor between the two given numbers.<br> 8.10
Bess [88]

Answer: GCF(8,10) = 2

Step-by-step explanation:

Factors of 8

1, 2, 4

Factors of 10

1, 2, 5

5 0
3 years ago
Which equation does this graph represent?
VARVARA [1.3K]

Answer:

B.

Step-by-step explanation:

I plugged it into a graphing calculator which got me this.

3 0
3 years ago
Identify the resulting probability as theoretical or experimental. The outcomes for rolling a number cube with faces labeled 1−
fomenos
The answer is C.
there are 3 number that are equal or greater than 4 which are:4 ,5 and 6.
3/6 = 1/2

it is theoretical because you didn't do it experimentally.
4 0
3 years ago
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What’s da answer<br> Need helps
natima [27]

Answer:

I think the answer is 432 cubic inches( in^3). Answer is the first option.

6 0
3 years ago
Which point on the graph of g(x)=(1/5)^x? HELPP
Cloud [144]

Answer:

(-1,5) and (3, \frac{1}{125}) are points on the graph

Step-by-step explanation:

Given

g(x) = \frac{1}{5}^x

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-1}

Convert to index form

g(x) = 1/(\frac{1}{5})

Change / to *

g(x) = 1*(\frac{5}{1})

g(x) = 5

This satisfies (-1,5)

<em>Hence, (-1,5) is on the graph</em>

<em></em>

B. (1,0)

x = 1

Substitute 1 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^1

g(x) = \frac{1}{5}

<em>(1,0) is not on the graph because g(x) is not equal to 0</em>

C. (3, \frac{1}{125})

x = 3

Substitute 3 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^3

Apply law of indices

g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}

g(x) = \frac{1}{125}

This satisfies (3, \frac{1}{125})

<em>Hence, </em>(3, \frac{1}{125})<em> is on the graph</em>

<em></em>

D.  (-2, \frac{1}{25})

x = -2

Substitute -2 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-2}

Convert to index form

g(x) = 1/(\frac{1}{5}^2)

g(x) = 1/(\frac{1}{5}*\frac{1}{5})

g(x) = 1/(\frac{1}{25})

Change / to *

g(x) = 1*(\frac{25}{1})

g(x) = 25

This does not satisfy  (-2, \frac{1}{25})

<em>Hence, </em> (-2, \frac{1}{25})<em> is not on the graph</em>

8 0
4 years ago
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