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2 years ago

I GIVE BRAINLEST !! PLS SLOLVE

Mathematics

1 answer:

alexdok [17]2 years ago

8 0

Answer:

√6/2+1

Step-by-step explanation:

multiplying by √6/√6, we get √6(3+√6)/6=(3√6+6)/6=√6/2+1

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What is the mean, median, mode, and range of this data set, 2,3,2,4,3,3,3,4,2,3,4,2,4,4,9,3,4,4

slava [35]

Answer:

Mean: 3.5

Median: 3

Mode: 4

Range: 7

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is 10+12.50h=5+15h? Solve for h and show your work please.

irakobra [83]

Answer:

10+12.50h=5+15h

We move all terms to the left:

10+12.50h-(5+15h)=0

We add all the numbers together, and all the variables

12.50h-(15h+5)+10=0

We get rid of parentheses

12.50h-15h-5+10=0

We add all the numbers together, and all the variables

-2.5h+5=0

We move all terms containing h to the left, all other terms to the right

-2.5h=-5

h=-5/-2.5

h=+2

Step-by-step explanation:

please heart and give brainliest

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2 years ago

What is the equation of the line that is perpendicular to the given line and has an x-intercept of -3?

Anvisha [2.4K]

Answer:

$y=-\frac{3}{2}x-\frac{9}{2}$

Step-by-step explanation:

Let the equation of the perpendicular line is,

y = mx + b

where m = slope of the line

b = y-intercept

From the graph, slope of the line passing through (0, -1) and (3, 1),

m' = $\frac{y_2-y_1}{x_2-x_1}$

m' = $\frac{1+1}{3-0}$

m' = $\frac{2}{3}$

To get the slope (m) of this line we will use the property of perpendicular lines,

m × m' = (-1)

m × $\frac{2}{3}$ = -1

m = $-\frac{3}{2}$

Equation of the perpendicular line will be,

$y=-\frac{3}{2}x+b$

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)

0 = $-\frac{3}{2}(-3)+b$

b = $-\frac{9}{2}=-4.5$

Equation of the line will be,

$y=-\frac{3}{2}x-\frac{9}{2}$

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3 years ago

Select All That Apply .

makvit [3.9K]

Answer:

the 4th one ,hoped this help

7 0

3 years ago

Determine the amplitude or period as requested. Period of a y = - 1/3 * sin x - 1/3 pi/3 1/3 d 2pi

zysi [14]

Answer:

$Period = 2\pi$

Step-by-step explanation:

Given

$y = -\frac{1}{3} * \sin(x - \frac{1}{3})$

Required

Determine the period

A sine function is represented as:

$y =A \sin(Bx + C) + D$

Where

$Period = \frac{2\pi}{B}$

By comparing:

$y =A \sin(Bx + C) + D$ and $y = -\frac{1}{3} * \sin(x - \frac{1}{3})$

$Bx = x$

So:

$B = 1$

So, we have:

$Period = \frac{2\pi}{B}$

$Period = \frac{2\pi}{1}$

$Period = 2\pi$

Hence, the period of the function is $2\pi$

6 0

3 years ago