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katen-ka-za [31]
2 years ago
9

When Sherron inputs the equation 4x + 3 = 4(1 + x) + 1, she gets a error message. Explain why.

Mathematics
1 answer:
astraxan [27]2 years ago
6 0

Answer:

She gets

Step-by-step explanation:

She gets an error message because when solving a linear equation, the coefficient of the variable is not meant to be the same on both sides of the equation because it will equal 0 in the end. In this equation, you will get 4x on both sides and then the last step will be 0= 3. This is an error.

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A ship is anchored off a long straight shoreline that runs north and south. From two observation points 16 miles apart on shore,
ELEN [110]
D - the shortest distance from the ship to the shore.
d / ( 17 - x ) = tan 32° = 0.62487
d / x = tan 53° = 1.32704
d = 0.62487 ( 17 - x )
d = 1.32704 x
0.62487 ( 17 - x ) = 1.32704 x
10.62279 - 0.62487 x = 1.32704 x
x = 10.62279 : 1.95191
x = 5.44226 miles
d = 5.44226 · 1.32704
Answer:
d = 7.222  miles
6 0
3 years ago
. one decimal place
SOVA2 [1]

Answer:

1. 168

2. 70

3. 15

Hope that this helps!

3 0
3 years ago
Read 2 more answers
The U.S.A. Olympic Synchronized Swimming Team is designing a routine for their upcoming competition. From the center of the pool
Mama L [17]

Answer:

The equation of the circle is;

(x - 2)² + (y - 4)² = 5²  

Step-by-step explanation:

We note that the general equation of a circle is given as follows;

(x - h)² + (y - k)² = r²

Where;

(h, k) = The coordinates of the center of the circle

r = The radius of the circle

The given parameters are;

The location of the center of the pool to the center of their formation = 2 feet to the right and 4 feet up from the center of the pool

The point through which the circle which they form goes through = A point 3 feet to the left and 4 feet up from the center of their formation

Taking the center of the pool as the origin of the coordinate plane system, we have;

The coordinate of the center of the circle = The coordinate of their motion from the center of the circle

∴ The coordinate of the center of the circle = (2, 4)

∴ (h, k) = (2, 4)

h = 2, k = 4

The coordinate of the point through which the circle passes = (2 - 3, 4 + 4) = (-1, 8)

∴ The length of the radius, 'r', can be found as, r = √((-3)² + 4²) = 5 or r = √((-1 - 2)² + (8 - 4)²) = 5

r = 5

The equation of the circle is therefore presented by substituting the values of 'h', 'k', and 'r', as follows;

(x - 2)² + (y - 4)² = 5².

4 0
3 years ago
Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in
kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let y\in (x-\epsilon,x+\epsilon). then we have that x-\epsilon. Hence, it makes sense to define the positive number delta as \delta=\min\{x+\epsilon-y,y-(x-\epsilon)\} (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon), and if we prove this, we are done. To prove it, let z\in (y-\delta,y+\delta), then y-\delta. First, \delta \leq y-(x-\epsilon) then -\delta \geq -y+x-\epsilon hence z>y-\delta \geq x-\epsilon

On the other hand, \delta \leq x+\epsilon-y then z hence z. Combining the inequalities, we have that  x-\epsilon, therefore (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon) as required.  

3 0
3 years ago
A ladder is placed against a wall, such that it touches the top of the wall 6 meters above the ground. The ladder is inclined at
luda_lava [24]

Your answer would be.

3.46 meters

-Yaoii

7 0
3 years ago
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