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Novosadov [1.4K]
2 years ago
6

A city has a population of 340,000 people. Suppose that each year the population grows by 4.25%. What will the population be

Mathematics
1 answer:
WINSTONCH [101]2 years ago
6 0

Answer:

approximately 500,000

Step-by-step explanation:

1 year- 340,000

2 year- 354450

3 year-368900

4 year-383350

5 year-397800

6 year-412250

7 year-426700

8 year-441150

9 year-455600

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26 * 15 = 390, so your answer is 15 cm.
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The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1
evablogger [386]

Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\

We have to calculate a 98% confidence interval for the mean.

The population standard deviation is know and is σ=39.

The sample mean is M=2169.67.

The sample size is N=15.

As σ is known, the standard error of the mean (σM) is calculated as:

\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{39}{\sqrt{15}}=\dfrac{39}{3.873}=10.07

The z-value for a 98% confidence interval is z=2.326.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=2.326 \cdot 10.07=23.43

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 2169.67-23.43=2146\\\\UL=M+t \cdot s_M = 2169.67+23.43=2193

The 98% confidence interval for the population mean is (2146, 2193).

3 0
3 years ago
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