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nikdorinn [45]
2 years ago
6

Now find another real world example (it can be a similar range problem). Graph it on a number line, and then explain the minimum

and maximum of the range. Write it as an absolute value and using what you have learned about solving absolute values, demonstrate that your equation is represented by the graph.
Mathematics
1 answer:
Kaylis [27]2 years ago
8 0

The real world example for the absolute value are to express the change in balance of account.

How to use absolute value in real world problem?

Absolute value in real world problem is used to express the change or variation from one point to another point. In the absolute value, the sign of the number is not consideredd.

Let a real world example-

  • Everyone is going with 20 km/h and a person x is going with 15 km/h.
  • The person x has most likely to get the token as the difference between his speed and public speed is 5 km/h.
  • The sign of the number is not considered, whether it is +5 or -5 it is the difference of 5 km/h.
  • The number line for this absolute value is plotted below.

The real world example for the absolute value are to express the change in balance of account.

Learn more about absolute value in real world problem here:

brainly.com/question/2235065

#SPJ1

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10 points! please help!
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How many pairs of whole numbers can you find that have a sum of 12
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The volume of a cylinder is 12,566.4 cm3. The height of the cylinder is 8 cm.
scoundrel [369]
Using the formulas here: http://www.1728.org/diamform.htm

A)  Volume   =   <span>π <span>• r² • height
radius^2 = Volume / (PI*height)
</span></span><span>radius^2 = 12,566.4 / (PI * 8)
</span>radius^2 =  <span> <span> <span> 500.0011692175 </span> </span> </span>
radius = <span> <span> <span> 22.3607059195 </span> </span> </span>
radius (rounded) = 22.4 cm

B) Area of base = PI * radius^2
Area of base = 3.14159265 * 500
Area of base = <span> <span> <span> 1,570.7963267949 </span>
</span></span><span><span>Area of base (rounded) = </span> 1,570.8 square cm
</span> 
C) <span><span>lateral area = </span>2 • </span><span>π • r • height </span>
<span>lateral area = 2 • </span><span>π • 22.4 * 8
</span>lateral area = <span> <span> <span> 1,125.9468070466 </span> </span> </span>
lateral area = 1,125.9 <span>square cm

D) Total Surface Area = </span><span>(2 • <span>π <span>• r²) + (2 • <span>π • r • height)</span></span></span></span>
Total Surface Area = <span><span>2 * (top AND bottom area which is the Part B answer times 2) + (the lateral area which is the Part C answer)
</span>
Total Surface Area = </span>( 2 * 1,570.8 ) + (1,125.9)
<span>Total Surface Area = 3,141.6 + 1,125.9
</span><span>Total Surface Area = </span> <span> <span> <span> 4,267.5 </span> </span> </span> square cm





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