Answer:
The surface area of the pyramid is 335,673 cubit² or 134,269,200 in.²
Step-by-step explanation:
Here we have that the formula for the lateral surface area of a square pyramid is given as follows;
Lateral surface area = 2 × b × h
Where:
b = Base length = 453 cubits
h = Slant height
∴ 260,928 = 2 × 453 × h
Hence;
h = (260,928)/(2 × 453) = 288 cubits
We therefore have
Length of side, s = 453 cubits = 453*20 inches = 9060 in.
Slant height = 288*20 inches = 3300 in.
Surface area of the pyramid = A + 1/2 × p × s
Where:
A = Area of the base = s² = 453² = 205209 cubit²
p = Perimeter of base = 2×s = 2×453 = 906 cubit
s = Slant height = 288 cubit
∴ Surface area of the pyramid = 205209 + 1/2 × 906× 288
Surface area of the pyramid = 335,673 cubit²
1 cubit = 20 in
∴ 1 cubit² = 400 in²
335,673 cubit² = 400×335,673 = 134,269,200 in.² = 932,425 ft²
