Ask question

Ask question

All categories

2 years ago

10

Find x. Round your answer to the nearest tenth of a degree. plz help!

1 answer:

Nuetrik [128]2 years ago

7 0

Answer:

36.9°

Step-by-step explanation:

The relevant trig relation is ...

Cos = Adjacent/Hypotenuse

cos(x) = 8/10 = 0.8

The inverse trig function is used to find the angle:

x = arccos(0.8) ≈ 36.9°

You might be interested in

What’s the answer. Please respond fast

8_murik_8 [283]

The answer to your problem is 108.18

7 0

3 years ago

State if the polygons are similar

Mashutka [201]

Polygons are similar? Well there is no picture provided, so I have no idea what you're talking about. But I think you might be asking if in general all polygons are similar, and if that's the case, they are not. Similar means they are similar in at least one aspect, and all polygons are different from each other, only adding one line for each bigger polygon. So I don't know if this helped you, but I tried anyways.

4 0

3 years ago

Consider the graph of the function f(x)=10^x

Sidana [21]

Step-by-step explanation:

B. Is correct, the graph will never touch 0 if we shift the graphs horizontally,

4 0

2 years ago

Read 2 more answers

2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?

mezya [45]

Answer:

the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

Step-by-step explanation:

We need to find inverse of the quadratic function $f(x) = x^2 - 3$

Let

$y=x^2-3$

Replace x and y

$x=y^2-3$

Now, we will solve for y

Adding 3 on both sides

$x+3=y^2-3+3$

$x+3=y^2$

Taking square root on both sides

$\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}$

Now replace y with $f^{-1}(x)$

$f^{-1}(x)=\pm \sqrt{x+3}$

So, the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

3 0

3 years ago

The terminal side of an angle in standard position passes through P(15, –8). What is the value of sine theta? sine theta = fifte

Pavlova-9 [17]

The value of sine theta = negative eight-seventeenths ⇒ 2nd

Step-by-step explanation:

Let us revise the quadrant of an angle its terminal side passes through a given point

If the given point is (x , y), then the angle lies in the 1st quadrant
If the given point is (-x , y), then the angle lies in the 2nd quadrant
If the given point is (-x , -y), then the angle lies in the 3rd quadrant
If the given point is (x , -y), then the angle lies in the 4th quadrant

∵ The terminal side of angle Ф passes through P (15 , -8)

∵ x = 15 and y = -8

- P is (x , -y), then the angle Ф lies in the 4th quadrant

∵ The terminal side of angle Ф is the hypotenuse of a right

triangle whose horizontal leg is 15 units and vertical leg

is -8 units

- Use Pythagoras Theorem to find the length of the hypotenuse

∴ Hypotenuse = $\sqrt{(15)^{2}+(-8)^{2}}=17$ units

∵ sinФ = $\frac{opposite}{hypotenuse}$

∵ The side opposite to Ф is -8

∵ The hypotenuse is 17

∴ sinФ = $\frac{-8}{17}$

The value of sine theta = negative eight-seventeenths

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

3 0

3 years ago

Read 2 more answers