Question

Which describes how the parent function, f(x) = |x|, is transformed to show the function f(x) = 0. 1|x – 3|? It is wider and shifted 3 units to the left. It is wider and shifted 3 units to the right. It is narrower and shifted 3 units to the left. It is narrower and shifted 3 units to the right.

Answer 1

The correct statement about the function is '' It is wider and shifted 3 units to the right''.

Given that

Function; $\rm f(x) = |x|$

We have to determine

Which describes how the parent function, f(x) = |x|, is transformed to show the function f(x) = 0. 1|x – 3|?

According to the question

The function is;

$\rm f(x) = |x|$

First, the function is translated right into 3 units.

So, we have:

$\rm f'(x) =|x-3|$

The function is enlarged horizontally by a factor of 0.1.

$\rm f''(x) =0.1|x-3|$

The above highlights mean that:

$\rm f'(x) =|x-3|$ will be wider than $\rm f(x) = |x|$.

Hence, It is wider and shifted 3 units to the right.

To know more about the Parent function click the link given below.

brainly.com/question/12401491