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arsen [322]
3 years ago
9

On a coordinate plane, a parabola opens down with solid circles along the parabola at (negative 3, negative 5), (negative 2, 0),

(negative 1, 3), (0, 4), (1, 3), (2, 0), (3, negative 5). Use the drop-down menus to identify the values of the parabola. Vertex = Domain = {x| } Range = {y| y ≤ }
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

vertex: (0,4) // domain: x is a real number // Range: 4

Step-by-step explanation:

just did the assignment

NARA [144]3 years ago
4 0

Answer:

Vertex =  (0, 4)

Domain = {x|x is a real number.}

Range = {y| y ≤  4}

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1. If a = -1 , the value of3a + 1 is ​
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f(a) = 3a + 1 \\ Now,\: a =  - 1 \\ f( - 1) = 3( - 1) + 1 \\ f( - 1) =  - 3 + 1 \\ \boxed{ f( - 1) =  - 2}

  • Therefore, <em><u>-2</u></em> is the right answer.
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Ms Sherman is preparing 5 and 5/8 cups of rice for his family reunion. She plans to use 1/4 of a cup for each serving. How many
Temka [501]

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4 0
3 years ago
Need to write steps and solve <br> thanks
nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}

As per the formula,  \frac{x_{1}+x_{2}}{2}=5, \frac{y_{1}+y_{2}}{2}=-11

Here x_{1}=3; y_{1}=5

Substituting the value of x_{1} we get,

\frac{3+x_{2}}{2}=5

3+x_{2}=5\times2

x_{2}=10-3

x_{2}=7

Substituting the value of x_{2} we get,

\frac{5+y_{2}}{2}=-11

5+y_{2}=-11\times2

y_{2}=-22-5

y_{2}=-27

So, the coordinates of V is (7,-27)

7 0
3 years ago
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