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svet-max [94.6K]
3 years ago
10

How do you solve 3(m + 5 + 9m)

Mathematics
2 answers:
olchik [2.2K]3 years ago
8 0
<h2>Answer :</h2>

= 3(m+5+9m)

= 3m+15+27m

= 30m+15

= 15(2m+1)

IceJOKER [234]3 years ago
3 0

Step-by-step explanation:

= 3(m+5+9m)

= 3m+15+27m

= 30m+15

= 15(2m+1)

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A neighborhood development that is 4 acres is to be divided into 2/3 acre lots.How many lots can be created
saul85 [17]

no of lots to be created=4/2/3=12/2=6

3 0
3 years ago
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If x and y are positive integers, what is the value of x + y ? x+y=15 xy=6
maks197457 [2]
The answer is 9+6= 15
7 0
4 years ago
Given f(x)=x^2+8x+13. Enter the quadratic function in vertex form in the box f(x)= ___
Olenka [21]

Answer:

f(x) = (x + 4)² - 3

Step-by-step explanation:

The equation of a quadratic function in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

f(x) = x² + 8x + 13

To obtain f(x) in vertex form use the method of completing the square

add/ subtract (half the coefficient of the x- term)² to x² + 8x

f(x) = x² + 2(4)x + 16 - 16 + 13

f(x) = (x + 4)² - 3 ← in vertex form

8 0
3 years ago
Help pls need help show your solution and then graph​
Stella [2.4K]

Answer:

Step-by-step explanation:

We can use the quadratic formula or factor, This looks hard to factor so we should use the quadratic formula.

ax^2 + bx + c

so

a=4

b=-9

c=2

you can try it by hand or use this:

https://www.calculatorsoup.com/calculators/algebra/quadratic-formula-calculator.php

you get x=2 and x=0.25 these are the x intercepts (where Y is zero and where the graph crosses the x axis)

so mark x=2 and x=0.25 with a dot on a number line and you can draw a straight line between them since that is the part of the graph that is below the x axis (because the equation has <0) it is a positive parabola because the "a" value is positive and the presence of a "b" value means part of the graph will be below the x axis

5 0
2 years ago
Find the area of the shaded portion intersecting between the two circles.
stich3 [128]

Answer:

Area shaded portion = 16/3 π - 8√3

Step-by-step explanation:

The shaded portion consists of 2 equal segment

∵ Two circles have the same radii = 4

∵ The the length of the common chord of the two circles =  4

∴ The central angle of each segment = π/3 (60° equilateral Δ)

∵ Area segment = area sector - area Δ

∵ Area sector = 1/2 r²Ф = 1/2 × (4)² × π/3 = 8/3 π

∵ Area Δ = 1/4 s² √3 = 1/4 × (4)² × √3 = 4√3

∴ Area segment = 8/3 π - 4√3

∴ Area shaded portion = 2(8/3 π - 4√3) = 16/3 π - 8√3

4 0
3 years ago
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