One data is missing. You need the volume of the pool or some data that permit you to calculate this volume.
The same statement given by you is part of a problem where you know a series of data that shows the time required to fill the pool at different flow rates:
flow rate time
60 gal/h 300 h => 60 gal/h * 300 h = 18,000 gal
45 gal/h 400 h => 45 gal/h * 400 h = 18,000 gal
36 gal/h 500 h => 36 gal/h * 500 h = 18,000 gal
30 gal/h 600 h => 30 gal/h * 600 h = 18,000 gal
So for, this pool to calculated (several times) that the volume is 18,000 gal.
Now you have two hoses one with a flow rate of 40 gal / h and the other with a flow rate of 60 gal/h.
The total flow rate is the sum of the two flow rates"
total flow rate = 40 gal/h + 60 gal/h = 100 gal/h
And you just must divide the volume of the pool (18,000 gal) by the total flow rate (100 gal/h) to get the time to fill the pool:
time = volume / flow rate = 18,000 gal / 100 gal/h = 180 h.
Answer: 180h
7.6375 =
1 Decimal Place = 7.6
<span>2 Decimal Place = 7.64
</span><span>3 Decimal Place = 7.638
</span><span>4 Decimal Place = 7.6375
</span>
So the answer is 7.64 .
The 3 rounds up because 7 is bigger than 5...
Answer:
no solution
Step-by-step explanation:
If first equation is divided by 2 and the second equation is divided by 3, we get two equations 2x+y=3 and 2x+y= 4. These two lines are parallel and there cannot be any solution to the system
Answer:
-5x^5 + 2x^3 - 6x should be your answer
Answer:
Graphic is showed in the figure below
Step-by-step explanation:
To graph the equations given, let's do a table for positive values of x, and, by replacing it in the equation, let's calculate the value of y. Knowing the coordinate points (x,y) we can build the graphic.
<em>x y= x + 1/x² y = 1/x</em>
1 2 1
2 2.25 0.2
3 3.11 0.33
4 4.06 0.25
When x->0 both equations -> ∞, because lim(1/x) x->0 = ∞
The graphic is showed below. In red there is y = 1 + 1/x² and in blue y = 1/x