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3 years ago

Rearrange y=1/2x+2 to make x the subject.

Mathematics

2 answers:

yarga [219]3 years ago

7 0

Subtract 2

y-2=1/2 x

Multiply by 2 to cancel out the denominator and to get 1 in front of x

2(y-2)=x

You can stop there or you can multiply out.

2y-4=x

zvonat [6]3 years ago

3 0

So to make x the subject, you need to isolate it to one side.

Firstly, subtract both sides by 2: $y-2=\frac{1}{2}x$

Next, multiply both sides by 2: $2(y-2)=x$

Lastly, distribute 2 to (y - 2) and <u>your final answer will be $2y-4=x$ </u>

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Thepotemich [5.8K]

Answer:

Steps-by-step explanation:

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2 years ago

Read 2 more answers

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

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3 years ago

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3 years ago

Complete the square: x^2-8x+21=6<br><br> Please show work

mina [271]

Answer:

x=5 and 3

Step-by-step explanation:

x^2-8x+21=6

x^2-8x+21+16=6+16

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2 years ago

Read 2 more answers

Lydia graphed ΔXYZ at the coordinates X (0, −4), Y (2, −3), and Z (2, −6). She thinks ΔXYZ is a right triangle. Is Lydia's asser

katrin [286]

Answer:

Option (4)

Step-by-step explanation:

Vertices of the triangle are X(0, -4), Y(2, -3) and Z(2, -6).

Slope of XY ( $m_{1}$ ) = $\frac{y-y'}{x-x'}$

= $\frac{-3+4}{2-0}$

( $m_{1}$ ) = $\frac{1}{2}$

Similarly, slope of XZ ( $m_{2}$ ) = $\frac{-6+4}{2-0}$

( $m_{2}$ ) = (-1)

$m_{1}\times m_{2}=-\frac{1}{2}$

Which should be (-1) if XY and XZ are perpendicular to each other.

Now we can say that XY and XZ are not perpendicular.

Therefore, Lydia's assertion that ΔXYZ is a right triangle is not correct.

Option (4) will be the answer.

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