-8y = -4x + 16
Y = 4/8x - 2
when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one. Check the picture below.
Answer:
C
Step-by-step explanation:
In order to be able to find the circumference in relation to radius, you have to use the formula C = 2πr
Hope this helped :)
1. The remaing area of the yard will be found as follows:
Area of the yard
A1=length*width=10x*15x=150x^2 yd^2
area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2
The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2
2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2
Area of the field
A2=length×width
A2=3x×6x=18x^2
Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units
2.1S + 4.8H = 2808
H = 2S
2.1S + 4.8(2S) = 2808
2.1S + 9.6S = 2808
11.7S = 2808
S = 2808/11.7
S = 240
H = 2S
H = 2(240)
H = 480
so the standard version (S) has 240 downloads and the high quality version (H) has 480 downloads
