1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vesnalui [34]
3 years ago
14

An inlet pipe can fill a swimming pool in 9 hours and an outlet pipe can empty the pool in 12 hours. Through an error, both pipe

s are left open. How long will it take to fill te pool?
Mathematics
1 answer:
Andrew [12]3 years ago
7 0

Answer:

36 hours.

Step-by-step explanation:

Let x represent time taken by both pipes to fill the tank.

We have been given that an inlet pipe can fill a swimming pool in 9 hours. So part of pool filled by inlet pipe in one hour would be \frac{1}{9}.

We are also told that an outlet pipe can empty the pool in 12 hours. The part of pool emptied by outlet pipe in one hour would be \frac{1}{12}.

Sine the time taken by both pipes to fill the tank is x hours, so part of pool filled by both pipes in one hour would be \frac{1}{x}.

We will get an equation using our given information as:

\frac{1}{x}=\frac{1}{9}-\frac{1}{12}

Let us solve for x.

\frac{1}{x}=\frac{1*12}{9*12}-\frac{1*9}{12*9}

\frac{1}{x}=\frac{12}{108}-\frac{9}{108}

\frac{1}{x}=\frac{12-9}{108}

\frac{1}{x}=\frac{3}{108}

Cross multiply:

3x=108

\frac{3x}{3}=\frac{108}{3}

x=36

Therefore, it will take 36 hours for both pipes to fill the tank.

You might be interested in
Which of the following are solutions to the inequality below select all that apply
KIM [24]
<h3>Answer:  n = -11</h3>

The other choices are false, so choice C is the only solution here.

==================================================

Explanation:

Draw a number line. You'll have 0 in the center, with positive values on the right. The positive values increase 1,2,3,4,... as you move from left to right.

The negative values will go in the opposite direction. When going from right to left, we have -1, -2, -3, -4, ...

See the diagram below.

Now plot an open hole at -7 on the number line. The open hole says that we exclude this value from the solution set. Then we shade everything to the left of the open circle. This visually describes all values smaller than -7. Something like -2 is not to the left of -7, meaning -2 < -7 is false. But a value like -10 is to the left of -7, making -10 < -7 true.

With that in mind, the answer is n = -11 since -11 is to the left of -7. Of the values in the answer choices, it's the only thing to the left of -7.

The value n = -7 cannot be the solution because n < -7 would become -7 < -7 which is false.

5 0
3 years ago
Sample Size for Proportion As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of gol
Dima020 [189]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can assume an estimated proportion of \hat p =0.5 since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

6 0
3 years ago
What is 62% of 25 ?<br> im horrible at this plz help
hodyreva [135]
62% of 25

'of' means multiplication.

\sf 62\%\times 25

Convert 62% to a decimal, divide it by 100(since percentages are parts of 100):

62/100 = 0.62

\sf 0.62\times 25

Multiply:

\sf\boxed{\sf 15.5}
4 0
3 years ago
Read 2 more answers
Need help plz ..................
DiKsa [7]

Answer:

ight so

Step-by-step explanation:

6 0
3 years ago
I need help on 5 - 11
nalin [4]

5-11.

Positive 5 minus negative 11=

11-5=6

Now is 11 greater or 5, 11 is. And what is the integer of 11? A negative.

Therefore, the answer is -6.

4 0
2 years ago
Other questions:
  • Amanda teaches the art of quilling to four students these students each teach the art of quilling to four other students if this
    10·2 answers
  • Which The number 15,247<br>are 15,274 is greater ? use the symbol (&lt;or&gt;)​
    13·2 answers
  • Which is the graph 3x + 5y=-15
    12·1 answer
  • Someone pls help I just need this one
    11·1 answer
  • Please help!!!!!! (fill the blank)
    15·2 answers
  • In a pass of 30 students 13 are boys
    12·1 answer
  • Matthew wants to estimate the mean height of students attending his college. He records the heights of 100 randomly selected stu
    8·1 answer
  • How i can answer this question
    15·2 answers
  • Jimmy has 26,387
    9·2 answers
  • Each factory at a candy company has 498 workers. There are 12 factories. )
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!