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2 years ago

Number 11 and 12. Solve for x and y. Please and thank you.

Mathematics

1 answer:

vlada-n [284]2 years ago

4 0

Answer:

11. x=18, y=5

12. x=17, y=9

Step-by-step explanation:

Use the angle property https://www.proprofs.com/quiz-school/story.php?title=angle-properties-parallel-lines (REFER TO THIS LINK)

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(look at the images) can i get help on these?

Svetlanka [38]

Answer:

see explanation

Step-by-step explanation:

JK + KL = JL , substitute values

2x + 1 + 6x = 81, that is

8x + 1 = 81 ( subtract 1 from both sides )

8x = 80 ( divide both sides by 8 )

x = 10

Thus JK = 2x + 2 = 2(10) + 1 = 20 + 1 = 21

KL = 6x = 6 × 10 = 60

--------------------------------------------------------------

JK + KL = JL , substitute values

2x + x + 2 = 5x - 10 , that is

3x + 2 = 5x - 10 ( subtract 3x from both sides )

2 = 2x - 10 ( add 10 to both sides )

12 = 2x ( divide both sides by 2 )

6 = x

Thus

JK = 2X = 2 × 6 = 12

KL = x + 2 = 6 + 2 = 8

JL = 5x - 10 = 5(6) - 10 = 30 - 10 = 20

------------------------------------------------------------

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = S(7, 3) and (x₂, y₂ ) = T(1, - 5)

d = $\sqrt{(1-7)^2+(-5-3)^2}$

= $\sqrt{(-6)^2+(-8)^2}$

= $\sqrt{36+64}$

= $\sqrt{100}$ = 10

3 0

3 years ago

A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?

Fynjy0 [20]

Answer:

The equation showing this situation is $D=b^2-4ac=0$

Step-by-step explanation:

Given : A quadratic equation of the form $ax^2 + bx + c=0$ has one real number solution.

To find : Which could be the equation?

Solution :

A quadratic equation in form $ax^2+bx+c=0$ has a solution $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ called a quadratic formula in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

1) If $D=b^2-4ac>0$ there are two real roots.

2) If $D=b^2-4ac=0$ there are one real roots.

3) If $D=b^2-4ac$ there are no real roots.

According to question,

A quadratic equation of the form $ax^2 + bx + c=0$ has one real number solution.

So, The equation showing this situation is $D=b^2-4ac=0$

6 0

3 years ago

Part C

makkiz [27]

a = 1, b =14 and y-coordinate is 6 when x = 0.

Solution:

Let us first write the equation of a line.

Take the points are (2, 2) and (6, 10).

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{10-2}{6-2}$

$$m=\frac{8}{4}$

m = 2

Point-slope formula:

$y-y_1=m(x-x_1)$

y - 10 = 2(x - 2)

y - 10 = 2x - 4

Add 10 on both sides,we get

y = 2x + 6

Equation of a line is y = 2x + 6.

To find (a, 8), substitute x = a and y = 8 in the equation,

8 = 2a + 6

Subtract 6 from both sides, we get

2 = 2a

a = 1

To find (4, b), substitute x = 4 and y = b in the equation,

b = 2(4) + 6

b = 8 + 6

b = 14

Substitute x = o in the equation.

y = 2(0) + 6

y = 6

The y-coordinate is 6 when x = 0.

7 0

3 years ago

An angle measures 14° more than the measure of its complementary angle. What is the measure of each angle?

Mars2501 [29]

Answer:Complementary angles are two angles whose degree measurements add up to 90 degrees. The first angle would be (x + 14.4) and its complementary angle would be x. Therefore, you would set up this problem as: x + (x + 14.4) = 902x + 14.4 = 902x = 75.6 x = 37.8 (one angle)And (x + 14.4) = 52.2 (other angle).

To check: 37.8 + 52.2 = 90

Step-by-step explanation:

7 0

2 years ago

HOW DO U COMBINE LIKE TERMS in math?? DO NOT LOOK IT UP :) THX

gayaneshka [121]

Answer:

See below

Step-by-step explanation:

"Like terms" are terms with the same variable or exponents.

You can add or subtract these just like you would with regular numbers.

Examples:

2x + 4x = 6x

5xy + 7xy = 12xy

6 $x^{2}$ + 5 $x^{2}$ = 11 $x^{2}$

Let me know if you need more examples or have any questions :)

6 0

3 years ago