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mamaluj [8]
2 years ago
11

Number 11 and 12. Solve for x and y. Please and thank you.

Mathematics
1 answer:
vlada-n [284]2 years ago
4 0

Answer:

11. x=18, y=5

12. x=17, y=9

Step-by-step explanation:

Use the angle property https://www.proprofs.com/quiz-school/story.php?title=angle-properties-parallel-lines (REFER TO THIS LINK)

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Because weightlessness in outer space causes astronauts to lose bone mass, at the end of each month, an astronaut has two percen
vlabodo [156]

Answer:

There will be 88.6% of her bone mass remaining when she returns to earth.

Step-by-step explanation:

According to the problem, the astronaut will have 2% less bone mass than at the beginning of that month. So let's say B_{0} is her original bone mass. In that case, her bone mass after the first month will be:

B_{1}=B_{0}(0.98)

on the second month, her bone mass will be:

B_{2}=B_{1}(0.98)=B_{0}(0.98)(0.98)=B_{0}(0.98)^{2}

on the third month, her bone mass will be:

B_{3}=B_{2}(0.98)=B_{0}(0.98)(0.98)(098)=B_{0}(0.98)^{3}

and so on, we can see a pattern here. The formula for her remaining bone mass can be generally written like this:

B_{n}=B_{0}(0.98)^{n}

where n is the number of months, so after 6 months, her remaining bone mass will be:

B_{6}=B_{0}(0.98)^{6}=0.886B_{0}

that 0.886 gives us the percentage as a decimal number. When turned into a percentage we get that:

There will be 88.6% of her bone mass remaining after 6 months.

7 0
3 years ago
A gasoline tank for a certain car is designed to hold 14.0 gal of gas. Suppose that the variable x = actual capacity of a random
MariettaO [177]

Answer:

A gasoline tank for a certain car is designed to hold 14.0 gal of gas.

\mu = 14

\sigma = 0.2

a)What is the probability that a randomly selected tank will hold at most 13.7 gal?

We are supposed to find P(x \leq 13.7)

z=\frac{x-\mu}{\sigma}

z=\frac{13.7-14}{0.2}

z=-1.5

Refer the z table for p value

p value = 0.0668

So, P(x \leq 13.7)= 0.0668

The probability that a randomly selected tank will hold at most 13.7 gal is  0.0668

b)What is the probability that a randomly selected tank will hold between 13.4 and 14.3 gal?

We are supposed to find P(13.4

z=\frac{x-\mu}{\sigma}

z=\frac{13.4-14}{0.2}

z=-3

P(x<13.4)=P(z<-3)= 0.0013

z=\frac{x-\mu}{\sigma}

z=\frac{14.3-14}{0.2}

z=1.5

P(x<14.3)= 0.9332

P(13.4

The probability that a randomly selected tank will hold between 13.4 and 14.3 gal is 0.9319

(c) If two such tanks are independently selected, what is the probability that both hold at most 14 gal?

We are supposed to find P(x \leq 14)

z=\frac{x-\mu}{\sigma}

z=\frac{14-14}{0.2}

z=0

Refer the z table for p value

p value = 0.5

So, P(x \leq 14)= 0.5

Two such tanks are independently selected, the probability that both hold at most 14 gal = 0.5 * 0.5 = 0.25

Hence If two such tanks are independently selected, the probability that both hold at most 14 gal is 0.25

3 0
3 years ago
The total cost (c) in dollars of renting a car for n days is given by the inequality LaTeX: c\ge125+50nc ≥ 125 + 50 n. What is t
zysi [14]

Answer:

<h3>6 days</h3>

Step-by-step explanation:

Given the inequality expression of the total cost (c) in dollars of renting a car for n days as c ≥ 125 + 50n

To get the maximum number of days for which a car could be rented if the total cost was $425, substitute c = 425 into the expression and find n

425 ≥ 125 + 50n

Subtract 125 from both sides

425 - 125 ≥ 125 + 50n  - 125

300≥ 50n

Divide both sides by 50

300/50≥50n/50

6 ≥n

Rearrange

n≤6

<em>Hence the maximum number of days for which a car could be rented if the total cost was $425 is 6days</em>

<em></em>

5 0
3 years ago
Can u help me with the bases,faces and edges for the cross section
garik1379 [7]
Wouldn’t the faces be the triangle parts ? Like p,q,o p,m,q n,o,q
7 0
3 years ago
A survey of UF students asked for their employment status and their year in school. The results appear below.
cestrela7 [59]

Answer:

There is no relationship between your year in school and having a job.

Step-by-step explanation:

In this instance, the chi sq test need to be performed.

Chi sq is used to determine if there is a significant relationship between two categorical variables.

The two variables here are year in school and employment status.

The two variables are independent(no relationship exists)

This implies that there is null hypothesis

Therefore, the Null Hypothesis is

There is no relationship between your year in school and having a job.

3 0
3 years ago
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