Answer:
A repeating decimal...
Step-by-step explanation:
Because the numbers after the decimal points keep repeating.
Answer:
10xy-5
Step-by-step explanation:
15xy-4+2xy-7xy-1 is the given expression.
I assume the directions say to simplify.
Group the xy terms together and group the constants together.
15xy+2xy-7xy-4-1
This is a demonstration of the commutative property.
Now I will use the distributive property to rewrite the first 3 terms as a multiplication:
(15+2-7)xy-5
10xy-5
Answer: (4, -9)
<u>Step-by-step explanation:</u>
Use elimination method. Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable. <em>I will be eliminating y</em>
6x + y = 15 → 2(6x + y = 15) → 12x + 2y = 30
-7x - 2y = -10 → 1(-7x + 2y = -10) → <u> -7x - 2y = -10</u>
5x = 20
x = 4
Next, replace "x" with "4" into either equation and solve for y.
6(4) + y = 15
24 + y = 15
y = -9
<u>Check:</u>
Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.
-7x - 2y = -10
-7(4) - 2(-9) = -10
-28 - -18 = -10
-28 + 18 = -10
-10 = -10
Answer:
r=45,041
Step-by-step explanation:
455=(94)(22)^2/r
455=(94)(484)/r
455=45,496/r
455r=45,496
r=45,041
Answer:
The area of the shaded portion of the figure is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The shaded area is equal to the area of the square less the area not shaded.
There are 4 "not shaded" regions.
step 1
Find the area of square ABCD
The area of square is equal to
where
b is the length side of the square
we have
substitute
step 2
We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):
The area of circle is equal to
The diameter of the circle is equal to the length side of the square
so
---> radius is half the diameter
substitute
Therefore, the area of 2 "not-shaded" regions is:
and the area of 4 "not-shaded" regions is:
step 3
Find the area of the shaded region
Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:
so
---> exact value
assume
substitute