(4x^2-25)/(2x-5)=14
we hates fractions so m ultiply both sides by (2x-5)
4x^2-25=14(2x-5)
4x^2-25=28x-70
add 70 to both sides
4x^2+45=28x
subtract 28x fromoth sides
4x^2-28x+45=0
use quadratic formula which is
if you have
ax^2+bx+c=0 then
x=

a=4
b=-28
c=45
subsitute
x=

x=

x=

x=

or

if we were to put 5/2 for x, the deonomentor would be equal to zero, so it cannot be used
answer is
x=9/2
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Answer:
x=-5-2yi/3+4i
y=3xi/2+6+15i/2
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Hello!
To do this you see how many times 5 goes into 7. As you can see it only goes in once. This gives us a whole number one. Since we took away 5 we have two sevens left. This gives us the mixed number below.

I hope this helps!
KH = 3(x + 2) + <span>3x - 4
KH = 3x + 6 + 3x - 4
KH = 6x + 2 = 44
6x = 42
x = 7
HJ = 3(x + 2)
HJ = 3(7 + 2)
HJ = 27</span>